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stepladder [879]
3 years ago
12

Which of the following are solution to 2X squared minus 8X -90

Mathematics
1 answer:
svetlana [45]3 years ago
4 0

Answer:

2(x+5)*(x-9)

Step-by-step explanation:

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Explain to another student how to solve the equation.
AveGali [126]

Answer:

Solve for X ( The question I did was an example )

Step-by-step explanation:

To solve and equation like 2x+9=30 you will have to isolate the number with a variable. You need to subtract 9 on both sides for that to happen.

2x=21

Now the next step is to divide. You have to divide to get the answer.

x=21/2

x= 10.5

5 0
2 years ago
Any 10th grader solve it <br>for 50 points​
kkurt [141]

Answer:

\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0  is proved for the sum of pth, qth and rth terms of an arithmetic progression are a, b,and c respectively.

Step-by-step explanation:

Given that the sum of pth, qth and rth terms of an arithmetic progression are a, b and c respectively.

First term of given arithmetic progression is A

and common difference is D

ie., a_{1}=A and common difference=D

The nth term can be written as

a_{n}=A+(n-1)D

pth term of given arithmetic progression is a

a_{p}=A+(p-1)D=a

qth term of given arithmetic progression is b

a_{q}=A+(q-1)D=b and

rth term of given arithmetic progression is c

a_{r}=A+(r-1)D=c

We have to prove that

\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)=0

Now to prove LHS=RHS

Now take LHS

\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)

=\frac{A+(p-1)D}{p}\times (q-r)+\frac{A+(q-1)D}{q}\times (r-p)+\frac{A+(r-1)D}{r}\times (p-q)

=\frac{A+pD-D}{p}\times (q-r)+\frac{A+qD-D}{q}\times (r-p)+\frac{A+rD-D}{r}\times (p-q)

=\frac{Aq+pqD-Dq-Ar-prD+rD}{p}+\frac{Ar+rqD-Dr-Ap-pqD+pD}{q}+\frac{Ap+prD-Dp-Aq-qrD+qD}{r}

=\frac{[Aq+pqD-Dq-Ar-prD+rD]\times qr+[Ar+rqD-Dr-Ap-pqD+pD]\times pr+[Ap+prD-Dp-Aq-qrD+qD]\times pq}{pqr}

=\frac{Arq^{2}+pq^{2} rD-Dq^{2} r-Aqr^{2}-pqr^{2} D+qr^{2} D+Apr^{2}+pr^{2} qD-pDr^{2} -Ap^{2}r-p^{2} rqD+p^{2} rD+Ap^{2} q+p^{2} qrD-Dp^{2} q-Aq^{2} p-q^{2} prD+q^{2}pD}{pqr}

=\frac{Arq^{2}-Dq^{2}r-Aqr^{2}+qr^{2}D+Apr^{2}-pDr^{2}-Ap^{2}r+p^{2}rD+Ap^{2}q-Dp^{2}q-Aq^{2}p+q^{2}pD}{pqr}

=\frac{Arq^{2}-Dq^{2}r-Aqr^{2}+qr^{2}D+Apr^{2} -pDr^{2}-Ap^{2}r+p^{2}rD+Ap^{2}q-Dp^{2}q-Aq^{2}p+q^{2}pD}{pqr}

\neq 0

ie., RHS\neq 0

Therefore LHS\neq RHS

ie.,\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0  

Hence proved

5 0
3 years ago
The value of a dirt bike decreases by 20% each year. If you purchased this dirt bike today for $500, to the nearest dollar how m
jeka94
The value of the bike after a year becomes only 80% of the value a year ago. In this given, the initial amount $500 should be multiplied by 80% 5 times. The answer would be $163.84. Thus, after 5 years the dirt bike would only be $163.84. 
5 0
3 years ago
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A researcher is using a regular, two-tailed test with α = .05 to determine whether a non-zero correlation exists in the populati
beks73 [17]

Answer:

Step-by-step explanation:

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7 0
3 years ago
30=11+3x find x need asap
kompoz [17]

Answer:

x = 19/3

Step-by-step explanation:

30 - 11 = 3x

3x = 19

x = 19/3

hope it helps!

4 0
3 years ago
Read 2 more answers
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