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snow_lady [41]
3 years ago
12

Please help me...will mark brainiest

Mathematics
2 answers:
Vlad1618 [11]3 years ago
5 0

Answer:

x² - 22x + 121

Step-by-step explanation:

(x-11)² is the same as (x-11)(x-11)

multiply the x in the first parentheses by x and -11 in the other parentheses and multiply the -11 in the first parentheses by x and -11 in the other parentheses and add all together

x²- 11x - 11x + 121

x² - 22x + 121

Gnoma [55]3 years ago
4 0

Answer:

x-121

Step-by-step explanation:

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Point A is located at (−2, −6), and D is located at (−6, 8). Find the coordinates of the point that lies halfway between A and D
Afina-wow [57]

Answer:

(-4,1)

Step-by-step explanation:

Point A is located at (−2, −6), and D is located at (−6, 8).

We need to find the midpoint of A  and D

Mid point formula is (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Point A is (-2,-6) that is (x1,y1)

Point D is (-6,8) that is (x2, y2)

plug in the values in the formula

(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

(\frac{-2-6}{2}, \frac{-6+8}{2})

(\frac{-8}{2}, \frac{2}{2})

Mid point is (-4, 1)

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3 years ago
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My rectangular soccer field site has a length equal to one and a half times it’s width. Find the area of its length x.
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Answer:

Let width = x

Let length = 1.5x

Area = (length)(width)

Area = 1.5x2

Step-by-step explanation:

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3 years ago
3^5 + 6^3 evaluate the expression
tigry1 [53]

Answer:

459

Step-by-step explanation:

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Choose the answer that shows what to do in the process step, and what the solution (answer is).
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Solve the following pair of equations simultaneously.
Alchen [17]

Answer:

No solutions.

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination
  • Solving systems of equations by graphing
  • Expanding
  • Finding roots of a quadratic
  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

Step-by-step explanation:

<u>Step 1: Define systems</u>

2x - y = 9

4x² + 3y² - 2x + y = 16

<u>Step 2: Rewrite systems</u>

2x - y = 9

  1. Subtract 2x on both sides:                    -y = 9 - 2x
  2. Divide -1 on both sides:                          y = 2x - 9

<u>Step 3: Redefine systems</u>

y = 2x - 9

4x² + 3y² - 2x + y = 16

<u>Step 4: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                         4x² + 3(2x - 9)² - 2x + (2x - 9) = 16
  2. Expand:                                    4x² + 3(4x² - 36x + 81) - 2x + (2x - 9) = 16
  3. Distribute 3:                             4x² + 12x² - 108x + 243 - 2x + 2x - 9 = 16
  4. Combine like terms:                16x² - 108x + 234 = 16
  5. Factor GCF:                              2(8x² - 54x + 117) = 16
  6. Divide 2 on both sides:           8x² - 54x + 117 = 8
  7. Subtract 8 on both sides:        8x² - 54x + 109 = 0
  8. Define variables:                      a = 8, b = -54, c = 109
  9. Resubstitute:                            x=\frac{54\pm\sqrt{(-54)^2-4(8)(109)} }{2(8)}
  10. Exponents:                               x=\frac{54\pm\sqrt{2916-4(8)(109)} }{2(8)}
  11. Multiply:                                    x=\frac{54\pm\sqrt{2916-3488} }{16}
  12. Subtract:                                   x=\frac{54\pm\sqrt{-572} }{16}

Here we see that we start to delve into imaginary roots. Since on a real number plane, we do not have imaginary roots, there would be no solution to the systems of equations.

<u>Step 5: Graph systems</u>

<em>We can verify our results.</em>

8 0
3 years ago
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