1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex17521 [72]
3 years ago
11

I need help! I don't really understand.... Can someone help for these 2 questions?? Part A and B??

Mathematics
1 answer:
vfiekz [6]3 years ago
8 0

Answer:

A. 6x + 4

B. 22 cm

Step-by-step explanation:

The perimeter of the triangle is equal to the sum of all the side lengths, which is (2x+3) + (x+1) + (3x), or 6x + 4.

When x = 3cm, the perimeter is 6(3) + 4, which is 22 cm.

You might be interested in
Diego has a standard 52 card playing deck, which includes
trapecia [35]

Answer:

13/52

Step-by-step explanation:

7 0
3 years ago
A bag contains red marbles, white marbles, and blue marbles. Randomly choose two marbles, one at a time, and without replacement
dsp73

Answer:

P(First\ White\ and\ Second\ Blue) = \frac{3}{28}

P(Same) = \frac{67}{210}

Step-by-step explanation:

Given (Omitted from the question)

Red = 7

White = 9

Blue = 5

Solving (a): P(First\ White\ and\ Second\ Blue)

This is calculated using:

P(First\ White\ and\ Second\ Blue) = P(White) * P(Blue)

P(First\ White\ and\ Second\ Blue) = \frac{n(White)}{Total} * \frac{n(Blue)}{Total - 1}

<em>We used Total - 1 because it is a probability without replacement</em>

So, we have:

P(First\ White\ and\ Second\ Blue) = \frac{9}{21} * \frac{5}{21 - 1}

P(First\ White\ and\ Second\ Blue) = \frac{9}{21} * \frac{5}{20}

P(First\ White\ and\ Second\ Blue) = \frac{9*5}{21*20}

P(First\ White\ and\ Second\ Blue) = \frac{45}{420}

P(First\ White\ and\ Second\ Blue) = \frac{3}{28}

Solving (b) P(Same)

This is calculated as:

P(Same) = P(First\ Blue\ and Second\ Blue)\or\ P(First\ Red\ and Second\ Red)\ or\ P(First\ White\ and Second\ White)

P(Same) = (\frac{n(Blue)}{Total} * \frac{n(Blue)-1}{Total-1})+(\frac{n(Red)}{Total} * \frac{n(Red)-1}{Total-1})+(\frac{n(White)}{Total} * \frac{n(White)-1}{Total-1})

P(Same) = (\frac{5}{21} * \frac{4}{20})+(\frac{7}{21} * \frac{6}{20})+(\frac{9}{21} * \frac{8}{20})

P(Same) = \frac{20}{420}+\frac{42}{420} +\frac{72}{420}

P(Same) = \frac{20+42+72}{420}

P(Same) = \frac{134}{420}

P(Same) = \frac{67}{210}

6 0
3 years ago
PLEASEEE HELP ME WITH THESE QUESTIONS I NEED IT FOR TOMORROW!!! THANK YOU SO MUCH : )
KiRa [710]
For the first problem the equation should be 2w-1

I also did this quickly in my head but it's most likely correct.
4 0
3 years ago
WILL GIVE BRAINLIEST!
zvonat [6]

Answer: c

Step-by-step explanation:

are going to mark me brainly

7 0
3 years ago
Read 2 more answers
if Mr man runs at 5 miles per hour Mister Gwen Hot Wheels at 3 miles per hour who will win the race? (using the Pythagorean theo
alisha [4.7K]

Answer:

I think youd need more info if youre using the pythagorean theorem, but with the given info, Mr man would bc hes going faster

Step-by-step explanation:

(P.S. Mr man sounds like a whole snacccccc) XD

8 0
3 years ago
Read 2 more answers
Other questions:
  • -4|7 - 6k| =14<br> please help idk how to solve this
    6·1 answer
  • Finding Slope On a coordinate plane, a line goes through points (0, 1) and (4, 2). What is the slope of the line? m =
    9·1 answer
  • Need this ASAP I don’t really know inequalities
    15·2 answers
  • The equation (x-7^2/64)+(y+2)^2/9=1 represents an ellipse.
    13·2 answers
  • Plz help me asap but faster
    14·2 answers
  • In order to purchase fencing to go around a rectangular​ yard, would you need to use perimeter or area to decide how much to​ bu
    5·1 answer
  • Which is another name for plane M?
    6·1 answer
  • Please hurry for quiz
    7·1 answer
  • Is the point (3, 11) a solution for the linear equation 1/3x + y = 12? Explain.
    11·1 answer
  • Pls anyone help for a big change in my grade
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!