Answer:
(3-1) + (1+3) = 4
Step-by-step explanation:
it is what i put there cause both letters you have to change it to a nuber thats makes the equation work up to 4
Answer:
79.986
Step-by-step explanation:
Let A represent isotope ⁷⁹Br
Let B represent isotope ⁸¹Br
From the question given above, the following data were obtained:
For Isotope A (⁷⁹Br):
Mass of A = 79
Abundance of A (A%) = 50.69%
For isotope B (⁸¹Br):
Mass of B = 81
Abundance of B (B%) = 49.31%
Relative atomic mass of Br =?
The relative atomic mass (RAM) of Br can be obtained as follow:
RAM = [(Mass of A × A%) /100] + [(Mass of B × B%) /100]
= [(79 × 50.69) /100] + [(81 × 49.31) /100]
= 40.0451 + 39.9411
= 79.986 amu
Thus, the relative atomic mass of Br is 79.986
Answer:
-6, -7
Step-by-step explanation:
basically
-4 5/8 - x >0
so
x< -4 5/8
you just need 2 values less than -4 5/8
like -6 and -7
The error is that the student measured the wrong side. Acute angles are less than 90 degrees. So it isn’t possible for the measure to be over 90. The correct measure is 49
Answer:
1/10
Step-by-step explanation:
Because there is ten different numbers so therefore it would be 10/1
