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ollegr [7]
3 years ago
13

Evaluate each function at the given value using the Remainder Theorem.

Mathematics
2 answers:
hodyreva [135]3 years ago
7 0

Answer:

C

Step-by-step explanation:

belka [17]3 years ago
3 0

Answer: C

Step-by-step explanation:

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What is 4(x-7)=2(x+3)?
hram777 [196]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

4(x−7)=2(x+3)

Simplify both sides of the equation.

4(x−7)=2(x+3)

4x+−28=2x+6

4x−28=2x+6

Subtract 2x from both sides.

4x−28−2x=2x+6−2x

x−28=6

Add 28 to both sides.

2x−28+28=6+28

2x=34

Divide both sides by 2.

2x/2  =  34/2

x = 17

5 0
3 years ago
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17.09 + 3.98 BENCHMARK!!!
Ahat [919]
21.07 beacuse when you add them all up you get that..
 
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3 years ago
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Law of radicals
andrey2020 [161]

Answer:

1)  \sqrt{x^7}=x^{\frac{7}{2}

2)  \sqrt[3]{y^5}=y^{\frac{5}{3}

3) \sqrt[5]{a^{12}}=a^{\frac{12}{5} }

4) \sqrt[4]{z^{9}}=z^\frac{9}{4}

Step-by-step explanation:

1) \sqrt{x^7}

We know that \sqrt{x}=x^{\frac{1}{2}

So, \sqrt{x^7}=x^{\frac{7}{2}

2) \sqrt[3]{y^5}

We know that \sqrt[3]{x}=x^{\frac{1}{3}

So, \sqrt[3]{y^5}=y^{\frac{5}{3}

3) \sqrt[5]{a^{12}}

We know that \sqrt[5]{x}=x^{\frac{1}{5}

So, \sqrt[5]{a^{12}}=a^{\frac{12}{5} }

4) \sqrt[4]{z^{9}}

We know that \sqrt[4]{x}=x^{\frac{1}{4}

So, \sqrt[4]{z^{9}}=z^\frac{9}{4}

6 0
3 years ago
Joey read in his biology book that fish activity increases with water temperature, and he decided to investigate this issue by c
balandron [24]

Answer:

Step-by-step explanation:

N

6 0
3 years ago
I don’t know how todo this correction .
blagie [28]

24/6  

24 can be divided by 6. 6 * 4 = 24.

24/6 = 4/1 = 4

5 0
3 years ago
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