Use the circle below to find the angle measures and arc measure
1 answer:
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The left-handed students
12% are left handed, percent means per hundred. Change percent into per 100.
12% =
Then simplify the fraction by dividing the numerator and denominator by 4
=
=
This is the fraction showing the proportion of the left-handed students
The right-handed students
Determine the fraction showing the proportion of the right-handed students
1 - the left-handed
= 1 -
Equalize the denominator to 25
Simplify
This is the proportion of the right-handed students
<span>Are there more right-handed or left-handed students?
There are more right-handed students than the left-handed students, because 21/25 is more than 3/25</span>
12% are left handed, percent means per hundred. Change percent into per 100.
12% =
Then simplify the fraction by dividing the numerator and denominator by 4
=
=
This is the fraction showing the proportion of the left-handed students
The right-handed students
Determine the fraction showing the proportion of the right-handed students
1 - the left-handed
= 1 -
Equalize the denominator to 25
Simplify
This is the proportion of the right-handed students
<span>Are there more right-handed or left-handed students?
There are more right-handed students than the left-handed students, because 21/25 is more than 3/25</span>
Answer:
The percentage of the students scored higher than 89% is 15.87%
Step-by-step explanation:
we are given
The average test scores for a particular test in algebra was 84
so, mean is 84
a standard deviation of 5
so,
we have
x=89
now, we can use z-score formula
now, we can plug values
now, we can use calculator
and we get
So,
The percentage of the students scored higher than 89% is 15.87%