<u>Answer:
</u>
The point-slope form of the line that passes through (6,1) and is parallel to a line with a slope of -3 is 3x + y – 19 = 0
<u>Solution:
</u>
The point slope form of the line that passes through the points 
and parallel to the line with slope “m” is given as
--- eqn 1
Where “m” is the slope of the line. 
are the points that passes through the line.
From question, given that slope “m” = -3
Given that the line passes through the points (6,1).Hence we get 
By substituting the values in eqn 1, we get the point slope form of the line which is parallel to the line having slope -3 can be found out.
y – 1 = -3(x – 6)
y – 1 = -3x +18
On rearranging the terms, we get
3x + y -1 – 18 = 0
3x + y – 19 = 0
Hence the point slope form of given line is 3x + y – 19 = 0
1.5 is lesser than 0.5. Oh, wait nevermind I meant to say -1.5 is lesser than 0.5
Answer:
yes, the point (-1, 5) is in the solution set
Step-by-step explanation:
y ≥ 2x + 3
Is 5 ≥ 2(-1) + 3? Yes
y + x > 0
Is 5 + (-1) > 0? Yes
Answer:
A: 71°
Explanation:
The interior angles of a triangle must always equal 180°.
We have two of the angles, and if we add them up and subtract it from 180°, we can get the missing angle.
49+60+x=180
Add 49 and 60
109+x=180
Isolate the x, so subtract 109 from 180
x=71°
Answer:
Slopes of perpendicular lines are the opposite reciprocal of each other. If you know the slope of one line, just multiply it by -1 and flip the fraction to find the perpendicular slope.
