Answer:
a) 0.0082
b) 0.9987
c) 0.9192
d) 0.5000
e) 1
Step-by-step explanation:
The question is concerned with the mean of a sample.
From the central limit theorem we have the formula:

a) 
The area to the left of z=2.40 is 0.9918
The area to the right of z=2.40 is 1-0.9918=0.0082

b) 
The area to the left of z=3.00 is 0.9987

c) The z-value of 1200 is 0
The area to the left of 0 is 0.5

The area to the left of z=1.40 is 0.9192
The probability that the sample mean is between 1200 and 1214 is

d) From c) the probability that the sample mean will be greater than 1200 is 1-0.5000=0.5000
e) 
The area to the left of z=-112.65 is 0.
The area to the right of z=-112.65 is 1-0=1
I'd do a little more than 77minutes for the 6and 7for if you could have it on 77and but you could have it in your head
HEY MATE YOUR ANSWER IS HERE
★ GIVEN EQUATION ★
X + Y = 4
★ SOLUTION ★
LET VALUE OF X = 0 , 1 , 2 , 3 AND 4
WHEN X = 0
0 + Y = 4
Y = 4
WHEN X = 1
1 + Y = 4
Y = 3
WHEN X = 2
2 + Y = 4
Y = 2
WHEN X = 3
3 + Y = 4
Y = 1
WHEN X = 4
4 + Y = 4
Y = 0
NOW OUR 5 COORDINATES OF LINE X + Y = 4 ARE
A ( 0 , 4)
B ( 1 , 3 )
C ( 2 , 2)
D ( 3 , 1 )
E ( 4 , 0 )
THANKS FOR YOUR QUESTION HOPE THIS HELPS
can i have a brill
thank u
good luck
Answer:
https://www.learncbse.in/ncert-solutions-for-class-7-maths/
Answer:
g(2) = 2
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given that 
Put x =2

= -1+3
= 2
g(2) = 2