Yes.
The definition of congruent circles is two circles with equal radii. Because the diameter is twice the radius, it is true that the diameters of two congruent circles are the same length.
Answer:
Therefore the dimensions of the garden is 16 feet by 13 feet.
Step-by-step explanation:
Let the length of the garden be x and the width of the garden be y.
Given that the area of the rectangular garden is 208 square feet.
Therefore,
xy =208

Again given that,
The garden is to be surrounded on three sides by a brick wall costing $ 8 per feet and the remaining sides by a fence costing $5 per feet.
The perimeter of the rectangle is = 2(length+ breadth)
= 2(x+y)
=2x+2y
The total cost of fence
![C= [ (2x\times 8)+(y\times 8)+(y\times 5)]](https://tex.z-dn.net/?f=C%3D%20%20%5B%20%282x%5Ctimes%208%29%2B%28y%5Ctimes%208%29%2B%28y%5Ctimes%205%29%5D)
= (16x+ 8y +5y)



To find the maximum or minimum point, we need to find out
and set
=0.

Then





Again 

Therefore at x= 13 , the cost is minimum.
Therefore x = 13 feet.
The other side of the garden is
feet = 16 feet.
Therefore the dimensions of the garden is 16 feet by 13 feet.
Given:
a + bi = 13 + 9i
Equate the real parts:
a = 13
Equate the imaginary parts:
b = 9
Answer:
a =13
b = 9
She earn $55,200
92,000 * .6 =
Answer:
P=0.147
Step-by-step explanation:
As we know 80% of the trucks have good brakes. That means that probability the 1 randomly selected truck has good brakes is P(good brakes)=0.8 . So the probability that 1 randomly selected truck has bad brakes Q(bad brakes)=1-0.8-0.2
We have to find the probability, that at least 9 trucks from 16 have good brakes, however fewer than 12 trucks from 16 have good brakes. That actually means the the number of trucks with good brakes has to be 9, 10 or 11 trucks from 16.
We have to find the probability of each event (9, 10 or 11 trucks from 16 will pass the inspection) . To find the required probability 3 mentioned probabilitie have to be summarized.
So P(9/16 )= C16 9 * P(good brakes)^9*Q(bad brakes)^7
P(9/16 )= 16!/9!/7!*0.8^9*0.2^7= 11*13*5*16*0.8^9*0.2^7=approx 0.02
P(10/16)=16!/10!/6!*0.8^10*0.2^6=11*13*7*0.8^10*0.2^6=approx 0.007
P(11/16)=16!/11!/5!*0.8^11*0.2^5=13*21*16*0.8^11*0.2^5=approx 0.12
P(9≤x<12)=P(9/16)+P(10/16)+P(11/16)=0.02+0.007+0.12=0.147