Question

Find for me the answer of this law to indices36^y-1 ×6^2y-2=1

Answer 1

Answer:

y = 1

Step-by-step explanation:

Given the equation: $36^{y-1}\times6^{2y-2}=1$

This equation can be turned into:

$6^{y-1}\times6^{y-1}\times6^{2y-2}=1$

Simplified to:

$6^{4y-4}=1$  (using the law of indices)

Since all numbers to the power of 0 equal 1:

∴ $4y-4=0$

Which concludes that y = 1.