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3 years ago

Find for me the answer of this law to indices36^y-1 ×6^2y-2=1

Mathematics

1 answer:

navik [9.2K]3 years ago

3 0

Answer:

y = 1

Step-by-step explanation:

Given the equation: $36^{y-1}\times6^{2y-2}=1$

This equation can be turned into:

$6^{y-1}\times6^{y-1}\times6^{2y-2}=1$

Simplified to:

$6^{4y-4}=1$ (using the law of indices)

Since all numbers to the power of 0 equal 1:

∴ $4y-4=0$

Which concludes that y = 1.

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the length of a rectangle is 4 times its width .if the perimeter of the rectangle is 60 M. what is the area

SSSSS [86.1K]

I think it would be 144 meters squared

6 0

4 years ago

Read 2 more answers

(4.3×10 2 )×(4.0×10 −3 ) in scientific notation??

DIA [1.3K]

(4.3×10²) × (4.0×10⁻³) in scientific notation?

(4.3 x 4.0) x (10² x 10⁻³) = 17.2 x (10² x 10⁻³) =

= 17.2 x 10²⁻³ = 17.2 x 10⁻¹ = 1.72 x 10¹ x 10⁻¹ = 1.72 x 10¹⁻¹ = 1.72 x 10⁰ = 1.72 x 1

Answer : 1.72 x 10⁰ = 1.72

Hope this helps!

$\textit{\textbf{Spymore}}$

4 0

4 years ago

Two boats leave port at noon. Boat 1 sails due east at 12 knots. Boat 2 sails due south at 8 knots. At 2 pm the wind diminishes

Ivan

Answer:

14.86 knots.

Step-by-step explanation:

<em>Given that:</em>

The boats leave the port at noon.

Speed of boat 1 = 12 knots due east

Speed of boat 2 = 8 knots due south

At 2 pm:

Distance traveled by boat 1 = 24 units due east

Distance traveled by boat 2 = 16 units due south

Now, speed of boat 1 changes to 9 knots:

At 3 pm:

Distance traveled by boat 1 = 24 + 9= 33 units due east

Distance traveled by boat 2 = 16+8 = 24 units due south

Now, speed of boat 1 changes to 8+7 = 15 knots

At 5 pm:

Distance traveled by boat 1 = 33 + 2 $\times$ 9= 51 units due east

Distance traveled by boat 2 = 24 + 2 $\times$ 15 = 54 units due south

Now, the situation of distance traveled can be seen by the attached right angled $\triangle AOB$ .

O is the port and A is the location of boat 1

B is the location of boat 2.

Using pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^{2} = 51^{2} + 54^{2}\\\Rightarrow AB^{2} = 2601+ 2916 = 5517\\\Rightarrow AB = 74.28\ units$

so, the total distance between the two boats is 74.28 units.

Change in distance per hour = $\dfrac{Total\ distance}{Total\ time}$

$\Rightarrow \dfrac{74.28}{5} = 14.86\ knots$

6 0

3 years ago

The length of a rectangular piece of steel in a bridge is 2 meters less than triple the width. The perimeter of the piece of ste

Sholpan [36]

This is an algebraic equation. First we have a square the width is X
The length is L=3X-2. P (perimeter is 44)
Therefore P = 2L+2X
= 2(3x-2) + 2x
= 6x - 4 + 2x
= 8x - 4
44+4=8x
x=48/8
x=6

Ans: Width is 6 metres and length is 16 metres

7 0

4 years ago

What is (5x-7)-(3x-4)?

Mekhanik [1.2K]

You will need to subtract 3x from 5x, then since there is a minus sign in front of the 7 it will count as a -7, so u add 7 cross it out and then add 7 to the -4(which is also negative cause it has a minus sign in front) and then you have ur answer

5x-3x=2x
7+ -4= 3
Answer: 2x-3

5 0

3 years ago