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SOVA2 [1]
3 years ago
12

Find the area of the following figure:

Mathematics
1 answer:
Sauron [17]3 years ago
6 0

Answer:

138

Step-by-step explanation

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Find the slope of the line passing through the points (4,4) and (6, -5)
Verdich [7]
I not sure if you mean the gradient of the line or the equation, so here is both.

Gradient (=m) :

( 4, 4 ) ( 6, 5 )
( x1 , y1) ( x2, y2 )

m = y2-y1 / x2-x1
= -5-4 / 6 - 4

= -9 / 2 (as a fraction)
= -4.5 (as a decimal)

Equation of the line :

m = -9/2

( 4, 4 )
( a, b )

y - b =m (x - a)
y - 4= -9/2 (x - 4)
(Multiply both sides by 2 to get rid of fraction)
2y - 4 = -9 (x - 4)
2y - 4 = -9x + 36
2y = -9x + 36 + 4
2y = -9x + 40

2y + 9x = 40

Please feel free to ask if you have any questions
8 0
3 years ago
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HELP PLEASE I WILL GIVE 50 POINTS AND MARK BRAINLESS TO BEST ANSWER​
dedylja [7]
Hahaha a while me as shaka a ana
5 0
3 years ago
Tickets to a movie cost $7.25 for adults and $5.50 for students a group of friends purchased 8 tickets for $52.75 how many adult
irina1246 [14]

Answer:

The number of adults tickets and student tickets purchased is 5 and 3.

Given that,

Tickets to a movie cost $7.25 for adults and $5.50 for students.

A group of friends purchased 8 tickets for $52.75.

Here we assume the no of adult tickets and no of student tickets be x and y.

Based on the above information, the calculation is as follows:

7.25x + 5.50y = 52.75 .............(i)

x + y = 8

x = 8 - y..................(2)

Now put the x value in the equation (1)

So,  

7.25(8-y) + 5.50y = 52.75

7.25 × 8 - 7.25y + 5.50y = 52.75

58 - 1.75y = 52.75

5.25 = 1.75y

y = 3

So,  

x = 8 - 3

= 5

Therefore we can conclude that the number of adults tickets and student tickets purchased is 5 and 3.

-Hope this helps<3

4 0
2 years ago
What is the value of the product (3-2)(3+21)?<br> 5<br> 9 +41<br> 9-41<br> 13
liraira [26]
(3 - 2)(3 + 21) = 9 + 63 - 6 - 42 = 72 - 6 - 42 = 66 - 42 = 24 (I got 24 as my final answer)
8 0
4 years ago
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What is the quotient of 15p^-4q^-6/-20p^-12q^-3 in simplified form?
musickatia [10]
\cfrac{15p^{-4}q^{-6}}{-20p^{-12}q^{-3}} =\cfrac{3p^{-4+12}}{-4q^{-3+6}} =- \cfrac{3p^{8}}{4q^{3}}
3 0
3 years ago
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