Answer:
The probability that a jar contains more than 466 g is 0.119.
Step-by-step explanation:
We are given that a jar of peanut butter contains a mean of 454 g with a standard deviation of 10.2 g.
Let X = <u><em>Amount of peanut butter in a jar</em></u>
The z-score probability distribution for the normal distribution is given by;
Z =
~ N(0,1)
where,
= population mean = 454 g
= standard deviation = 10.2 g
So, X ~ Normal(
)
Now, the probability that a jar contains more than 466 g is given by = P(X > 466 g)
P(X > 466 g) = P(
>
) = P(Z > 1.18) = 1 - P(Z
1.18)
= 1 - 0.881 = <u>0.119</u>
The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.
To solve this, I would just find what two adult tickets and one child ticket wold be worth.
To find that, just do:
5.20 + 9.90 * 2, which makes 25.
So now you just find how many 25s are in 900, or 36.
So 36 children's tickets were sold that day.
Hope I helped :)
Answer:

Step-by-step explanation:

Cross multiply,
y(x - 8) = x +3
yx - 8y = x + 3
yx - 8y -x = 3
yx - x = 3 + 8y
(y - 1)x = 3 +8y

their relative speed is 4 mph. so we put
4 mph = (25 mi)/x => x=25/4.
Well there are no even numbers in there, so the probability of taking one out must be 0