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3 years ago

14

A rotating sprinkler sprays a steady stream of water that is 9 feet long. If the sprinkler makes a full rotation, what is the ap

proximate circumference of the circular area it sprays with water?

1 answer:

monitta3 years ago

5 0

Answer:

it is 55

Step-by-step explanation:

You might be interested in

stich3 [128]

Answer:

C

Step-by-step explanation:

Because you should be subtract each other by 20x to transfer from side to another side.

4 0

3 years ago

Read 2 more answers

What expression is equivalent to 4x(3+y)

Sholpan [36]

Answer:

12x+4xy

Step-by-step explanation:

4x(3+y)

12x+4xy

You distribute the 4x in the parenthesis

7 0

3 years ago

This is confusion please help

oksano4ka [1.4K]

Answer:

c = 5√5

Step-by-step explanation:

When we have a right triangle, there is a property about its measurements that is <em>always</em> true, and its called the "Pythagorean Theorem"

First, let's understand the basic terms we use to describe the sides of a triangle:

we can call one leg "a", the other leg "b" and the slanted side "c"

("c" is also called the hypotenuse--and it's always opposite the 90-degree angle)

the pythagorean theorem:

a² + b² = c²

here, our "a" is 5, our "b" is 10 {and we don't know what c is}

let's try plugging these values into our formula:

a² + b² = c²

5² + 10² = c²

25 + 100 = c²

125 = c²

now, we know what c² is--but we want to know c,

so we must take the square root of both sides

√125 = √c²

√125 = c

now, while √125 <em>is </em>our answer, we can simplify further!

this is because 125 can be made up of 5 · 25

so, $\sqrt{125} = \sqrt{5*25}$

and

$\sqrt{5*25}=\sqrt{5}*\sqrt{25}$

we can take out the square root of 25 (5):

$=\sqrt{5}*5$

we write this as such: $5\sqrt{5}$

so, in simplest radical form, c = 5√5

(√125)

hope this helps!! have a lovely day :)

4 0

2 years ago

Which descriptions from the list below accurately describe the relationship

yarga [219]

Answer:

QUT

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The volume of a sphere whose diameter is 18 centimeters is _ cubic centimeters. If it’s diameter we’re reduced by half, it’s vol

kaheart [24]

<h2>Answer:</h2>

<u>First Part</u>

Given that

$Volume = \frac{4}{3} \pi r^{3}$

We have that

$Volume = \frac{4}{3} \pi r^{3} = \frac{4}{3} \pi (\frac{Diameter}{2})^{3} = \frac{4}{3} \pi 9^{3} = 972\pi cm^{3} \approx 3053.63 cm^{3}$

<u>Second Part</u>

Given that

$Volume = \frac{4}{3} \pi r^{3}$

If the Diameter were reduced by half we have that

$Volume = \frac{4}{3} \pi r^{3} = \frac{4}{3} \pi (\frac{r}{2}) ^{3} = \frac{\frac{4}{3} \pi r^{3}}{8}$

This shows that the volume would be $\frac{1}{8}$ of its original volume

<h2>Step-by-step explanation:</h2>

<u>First Part</u>

Gather Information

$Diameter = 18cm$

$Volume = \frac{4}{3} \pi r^{3}$

Calculate Radius from Diameter

$Radius = \frac{Diameter}{2} = \frac{18}{2} = 9$

Use the Radius on the Volume formula

$Volume = \frac{4}{3} \pi r^{3} = \frac{4}{3} \pi 9^{3}$

Before starting any calculation, we try to simplify everything we can by expanding the exponent and then factoring one of the 9s

$Volume = \frac{4}{3} \pi 9^{3} = \frac{4}{3} \pi 9 * 9 * 9 = \frac{4}{3} \pi 9 * 9 * 3 * 3$

We can see now that one of the 3s can be already divided by the 3 in the denominator

$Volume = \frac{4}{3} \pi 9 * 9 * 3 * 3 = 4 \pi 9 * 9 * 3$

Finally, since we can't simplify anymore we just calculate it's volume

$Volume = 4 \pi 9 * 9 * 3 = 12 \pi * 9 * 9 = 12 * 81 \pi = 972 \pi cm^{3}$

$Volume \approx 3053.63 cm^{3}$

<u>Second Part</u>

Understanding how the Diameter reduced by half would change the Radius

$Radius =\frac{Diameter}{2}\\\\If \\\\Diameter = \frac{Diameter}{2}\\\\Then\\\\Radius = \frac{\frac{Diameter}{2} }{2} = \frac{\frac{Diameter}{2}}{\frac{2}{1}} = \frac{Diameter}{2} * \frac{1}{2} = \frac{Diameter}{4}$

Understanding how the Radius now changes the Volume

$Volume = \frac{4}{3}\pi r^{3}$

With the original Diameter, we have that

$Volume = \frac{4}{3}\pi (\frac{Diameter}{2}) ^{3} = \frac{4}{3}\pi \frac{Diameter^{3}}{2^{3}}\\\\ = \frac{4}{3}\pi \frac{Diameter^{3}}{2 * 2 * 2} = \frac{4}{3}\pi \frac{Diameter^{3}}{8}\\\\$

If the Diameter were reduced by half, we have that

$Volume = \frac{4}{3}\pi (\frac{Diameter}{4}) ^{3} = \frac{4}{3}\pi \frac{Diameter^{3}}{4^{3}}\\\\ = \frac{4}{3}\pi \frac{Diameter^{3}}{4 * 4 * 4} = \frac{4}{3}\pi \frac{Diameter^{3}}{4 * 2 * 2 * 4} = \frac{4}{3}\pi \frac{Diameter^{3}}{8 * 8} = \frac{\frac{4}{3}\pi\frac{Diameter^{3}}{8}}{8}$

But we can see that the numerator is exactly the original Volume!

This shows us that the Volume would be $\frac{1}{8}$ of the original Volume if the Diameter were reduced by half.

3 0

2 years ago