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3 years ago

Are DEF and RPQ Congruent?

Mathematics

2 answers:

telo118 [61]3 years ago

5 0

Yes, DEF and RPQ are congruent.

11Alexandr11 [23.1K]3 years ago

3 0

Answer: yes

Step-by-step explanation:

Can be mapped by 180

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In a bag of marbles, 6 are blue. The probability of picking out a blue marble from the bag is 3/5. How many marbles are in the b

postnew [5]

Answer: 3/5 = (6/10). There are 10 TOTAL marbles in the bag.

Step-by-step explanation:

Since it is a question of fractions, you can assume any reasonable number and work with the numbers. We know initially that there are 6 marbles and they are ALL blue and the rest are another color or colors. So BLUE = 6/10 and the other colors 4/10 for 2/5.

6 0

3 years ago

A set of 25 two digit numbers are listed below 10,17,20,23,24,28,32,39,42,25,26,52,55,58,61,65,66,72,75,78,79,85,94,97,98. What

eimsori [14]

Answer:

0.48

Step-by-step explanation:

Given the data:

10,17,20,23,24,28,32,39,42,25,26,52,55,58,61,65,66,72,75,78,79,85,94,97,98

Sum of each of the numbers :

1, 8, 2, 5, 6, 10, 6, 12, 6, 7, 8, 7, 20, 13, 7, 11, 12, 9, 12, 15, 16, 13, 13, 16, 17

Probability that sum of the number's digit is odd:

Number of odd sum / total numbers

Number of odd sum = 12

Total numbers = 25

12 / 25

= 0.48

3 0

3 years ago

The average daily high temperature in °C) in Karachi, Pakistan, on the tth day of the year is

kvasek [131]

Answer:

The highest would be 34 degrees Celsius and the lowest would be 24 degrees Celsius.

Step-by-step explanation:

What I did was make a graph. The 29 in the beginning of the function represents the vertical shift, meaning the "midline" would be y = 29. The -5 after the 29 represents the amplitude. From there, you can go 5 under 29 (24 degrees Celsius) and 5 over 29 (34 degrees Celsius).

3 0

3 years ago

In a class of 19 students, 3 are math majors. A group of four students is chosen at random. (Round your answers to four decimal

KatRina [158]

Answer:

(a) The probability is 0.4696

(b) The probability is 0.5304

Step-by-step explanation:

The total number of ways in which we can select k elements from a group n elements is calculate as:

$nCx=\frac{n!}{x!(n-x)!}$

So, the number of ways in which we can select four students from a group of 19 students is:

$19C4=\frac{19!}{4!(19-4)!}=3,876$

On the other hand, the number of ways in which we can select four students with no math majors is:

$(16C4)*(3C0)=(\frac{16!}{4!(16-4)!})*(\frac{3!}{0!(3-0)!})=1820$

Because, we are going to select 4 students form the 16 students that aren't math majors and select 0 students from the 3 students that are majors.

At the same way, the number of ways in which we can select four students with one, two and three math majors are 1680, 360 and 16 respectively, and they are calculated as:

$(16C3)*(3C1)=(\frac{16!}{3!(16-3)!})*(\frac{3!}{1!(3-1)!})=1680$