Answer:
2
Step-by-step explanation:
Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
Answer:
Total earned= $273
Step-by-step explanation:
Giving the following information:
Regular labor hours= $5.25
Overtime labor hours= $5.25*1.5= $7.875
<u>To calculate the total earned, we need to use the following formula:</u>
Regular labor hours= 40*5.25= 210
Overtime labor hours= 8*7.875= 63
Total earned= 210 + 63
Total earned= $273
No this is the awnser-3x+y=2
Answer:
x/7<-3
x<-21
Step-by-step explanation:
x/7<-3
multiply the seven to get rid of x denominator
x<-21
