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3 years ago

Can anyone help me please. will give you brainliest.

Mathematics

1 answer:

Alona [7]3 years ago

4 0

<h3>Answer:</h3>

DE is not included, AAS
DF is included, ASA

<h3>Explanation:</h3>

An angle is identifiede by its vertex. A side is identified by the vertices it lies between. When the vertices are X and Y, the side that lies between (is included) is side XY.

1. The angle vertices are E and F, so the side included between them would be side EF. The named side, DE, is not included.

The postulate naming is pretty straightforward. Each A represents an angle, and each S represents a side. The sequence of letters matches the sequence of the parts of the geometry. Thus AAS refers to a pair of angles with the side being not between them, while ASA refers to a pair of angles with the side between.

When you have two angles and a not-included side, the postulate you must invoke is the AAS postulate.

2. The explanation of 1 pretty much covers it. Side DF is (included) between angles D and F, so the ASA postulate applies.

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The force of gravity on Mars is different than on Earth. The function of the same situation on Mars would be represented by the

sweet-ann [11.9K]

Answer:

If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.

Step-by-step explanation:

Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

$v=v_0+a\,*\,t\\y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2$

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.

Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

$v=v_0+a\,*\,t\\0=v_0-g\,*\,t\\t=\frac{v_0}{t}$

When we use this to replace the 't" in the displacement formula, we et:

$y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2\\y-y_0=v_0\,(\frac{v_0}{g} )-\frac{g}{2} \,(\frac{v_0}{g} )^2\\y-y_0=\frac{1}{2} \frac{v_0^2}{g}$

This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)

And we can also answer the question about time, since given the same initial velocity $v_0$ , the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)

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2 years ago

Take 9.5 gallons 6 1/3 poured out how much water is left in the tank

elena55 [62]

We can first convert 9.5 into fraction :

9.5= 9 1/2

Then we can use deduction to find out the answer:

9 1/2 - 6 1/3

=19/2 - 19/3

We change it to the same denominator:

=19×3/6 - 19×2/6

= 57/6 - 38/6

= 19/6

Therefore there are 19/6 or 3 1/6 gallons left in the tank.

Hope it helps!

4 0

3 years ago

If f(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B9%7D" id="TexFormula1" title="\frac{1}{9}" alt="\frac{1}{9}" align=

boyakko [2]

Answer:

Solution given:

f(x) = $\frac{1}{9}$ x-2

let f(x)=y

y = $\frac{1}{9}$ x-2

interchanging role of x and y

x= $\frac{1}{9}$ y-2

x+2= $\frac{1}{9}$ y

y=9(x+2)

y=9x+18

F-¹(x)=9x+18

and

F-¹(-1)=9*-1+18=-9+18=9

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2 years ago

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Brums [2.3K]

The answer should be -10

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3 years ago

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The domain is all real numbers

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3 years ago

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