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Viktor [21]
2 years ago
12

STOP SENDING ME LINKS BUT I NEED HELP RN

Mathematics
1 answer:
Strike441 [17]2 years ago
6 0
45
1080 divided by 24
45

45 5lbs per hour
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A cube has surface area of 96 sq cm. What is the length of each edge of the cube?​
Sedbober [7]
96/6=16
Each side has area 16 sq cm.
Each edge length is sqrt(16)=4 cm
8 0
3 years ago
Solve the following system of equations algebraic<br> y=x^2+3x-29<br> y=2x-9
Lady bird [3.3K]

Step-by-step explanation:

Given equations:

       y  = x² + 3x - 29    ------ (i)

       y  = 2x - 9  ---------------- (ii)

Now to solve this problem, we must determine the value of x and y;

 Equate equations 1 and 2;

       x² + 3x - 29 = 2x - 9

       x² + 3x - 2x - 29 + 9  = 0

       x² + x - 20  = 0

       x² + 5x - 4x - 20  = 0

       x(x + 5 ) - 4(x + 5) = 0

      (x - 4) (x+ 5) = 0

       x  - 4  = 0 or x + 5  = 0

      x  = 4 or x = -5;

So;   solve for y now;

     y = 2x - 9

     input x  = 4 or x = -5;

    y  = 2(4) - 9 or y = 2(-5) - 9

    y = -1 or y = -19

7 0
3 years ago
How to write 9 thousands 3 hundreds 4 ones
Nataly [62]

the answer is 9304=9 thousands 3 hundreds 4 ones

5 0
3 years ago
Read 2 more answers
I NEED HELP PEOPLE LAST TIME
Hoochie [10]

29.

f(x) = -x^2-7x-6

As x \to \pm \infty, y \to - \infty.

This can be easily verified by looking at the graph (graph of a quadratic equation).

30.

The growth of a population is not linear, it's exponential.

31.

Exponential growth > polynomial, so y = 3^x.

35.

V(t) = 30\cdot (25)^{\frac{t}{20}}

The question is asking V(t) for t = 40.

V(40) = 30\cdot (25)^{\frac{40}{20}} \\~\\V(40) = 30\cdot 25^2 \\~\\V(40) = 30\cdot 625 \\~\\V(40) = 18750

36.

The point of symmetry of a quadratic equation y = ax^2+bx+c is at its vertice:

V_x = \dfrac{-b}{2a}

V_x = \dfrac{6}{2}

V_x = 3

The line is x= 3.

3 0
2 years ago
Find the value of p in the figure below.
nirvana33 [79]

From the chord theorem we have:

4\cdot4.5=6\cdot(2p-3)\\\\18=12p-18\\\\12p=18+18\\\\12p=36\qquad|:12\\\\\boxed{p=3}

6 0
3 years ago
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