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Furkat [3]
3 years ago
8

Find cos theta! Please Help With Explanation! 25 points!

Mathematics
1 answer:
-Dominant- [34]3 years ago
4 0

Let us first find the angle adjacent to θ. To find this we can construct a right triangle by drawing a line segment from the point (-12,5) straight down to the x-axis. Using right triangle trig...

tan(adjacent angle)=5/12

adjacent angle=22.62 degrees

Since the two angles make a linear pair.

θ=180-22.62=157.38 degrees

cos(157.38 degrees) = -0.92

answer: -0.92

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What is true about the completely simplified sum of the polynomials 3x squared y squared minus 2 x y to the power of 5 and negat
12345 [234]

Answer:

The sum is a binomial with a degree of 6.

Step-by-step explanation:

To find : What is true about the completely simplified sum of the polynomials 3x^2y^2-2xy^5 and -3x^2y^2+3x^4y ?

Solution :

The polynomials  3x^2y^2-2xy^5 and -3x^2y^2+3x^4y ,

The sum of polynomial is given by,

S=3x^2y^2-2xy^5+(-3x^2y^2+3x^4y)

On simplifying , we get,

S=3x^2y^2-2xy^5-3x^2y^2+3x^4y

S=-2xy^5+3x^4y

Therefore, the result obtained is a binomial with a degree of 6.

4 0
3 years ago
Two grapefruits and three oranges cost $1.95. Three grapefruits and two oranges cost $2.05.
geniusboy [140]

Answer:

  • one orange costs $0.35  and  one grapefruit costs $0.45

Step-by-step explanation:

<em>let grapefruits be g , let oranges be o</em>

so first equation:

→2g + 3o  = $1.95

→g = ($1.95 - 3o)/2

so second equation:

→ 3g + 2o = $2.05

→ g = ($2.05 - 2o)/3

Solving simultaneously:

→ ($2.05 - 2o)/3 = ($1.95 - 3o)/2

→ 2($2.05 - 2o) = 3($1.95 - 3o)

→ 4.1 - 4o = 5.85 - 9o

→ - 4o + 9o = 5.85 - 4.1

→ 5o = 1.75

→ o = $0.35

Therefore one orange costs $0.35

Then one grapefruit costs g → ($1.95 - 3o)/2

                                               → g = ($1.95 - 3(0.35))/2

                                               → g = 0.45

Therefore one grapefruit costs $0.45

4 0
2 years ago
PLEASE HELP WILL GIVE BRAINLIEST!!! What does the degree of a polynomial expression tell you about its related polynomial functi
Art [367]
Where an, an-1,a2, a1, a0 are constants. We call the term containing the highest power of x the leading term, and we call an the leading coefficient. The degree of the polynomial is the power of x in the leading term. We have already seen degree 0, 1, and 2 polynomials which were the constant, linear, and quadratic functions, respectively. Degree 3, 4, and 5
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2 years ago
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frez [133]

Answer:

What’s the question

Step-by-step explanation:

3 0
2 years ago
Simplify the expression. Quantity cosecant of x to the power of two times secant of x to the power of two divided by quantity se
Art [367]

Answer:

D. 1

Step-by-step explanation:

We have the expression, \frac{\csc^{2}x\sec^{2}x}{\sec^{2}x+\csc^{2}x}

We get, eliminating the cosecant function,

\frac{\sec^{2}x}{\frac{\sec^{2}x}{\csc^{2}x}+1}

As, sinx is reciprocal of cosecx and cosx is reciprocal of secx,

i.e. \frac{\sec^{2}x}{\frac{\sin^{2}x}{\cos^{2}x}+1}

i.e. \frac{1}{\cos^{2}x}\times \frac{\cos^{2}x}{\sin^{2}x+\cos^{2}x}

Since, we know that, \sin^{2}x+\cos^{2}x=1

Thus,

\frac{1}{\cos^{2}x}\times \frac{\cos^{2}x}{\sin^{2}x+\cos^{2}x}=1

So, after simplifying, we get that the result is 1.

Hence, option D is correct.

3 0
2 years ago
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