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Furkat [3]
3 years ago
8

Find cos theta! Please Help With Explanation! 25 points!

Mathematics
1 answer:
-Dominant- [34]3 years ago
4 0

Let us first find the angle adjacent to θ. To find this we can construct a right triangle by drawing a line segment from the point (-12,5) straight down to the x-axis. Using right triangle trig...

tan(adjacent angle)=5/12

adjacent angle=22.62 degrees

Since the two angles make a linear pair.

θ=180-22.62=157.38 degrees

cos(157.38 degrees) = -0.92

answer: -0.92

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uranmaximum [27]

Answer:

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Step-by-step explanation:

7 0
2 years ago
What are two fractions equivalent to 12/14
Andrews [41]

Hey there!

12/14

• BOTH NUMBERS HAVE THE COMMON FACTOR OF 2, SO WE CAN DIVIDE BOTH THE NUMERATOR (TOP number) FROM THE DENOMINATOR (BOTTOM number)

= 12 ÷ 2 / 14 ÷ 2

= 6/7

= 18/21

Therefore, your answer is: 6/7 or 18/21

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

3 0
2 years ago
Read 2 more answers
Please help me with this question!! I also need the steps
e-lub [12.9K]

Hi there!

\large\boxed{x = \frac{\pi}{3} \text{ and } \pi}

We are given:

cos(7x)cos(4x) = -1 - sin(7x)sin(4x)

Begin by moving all terms with variables to one side:

cos(7x)cos(4x) + sin(7x)sin(4x) = -1

The corresponding trig identity is cos(A - B). Thus:

cos(7x - 4x) = cos(7x)cos(4x) + sin(7x)sin(4x) = -1

cos(3x) = -1

cos = -1 at  π, so:

3x = π

x = π/3

We can also find another solution. Let 3π = -1:

3x = 3π

x = π

Thus, solutions on [0, 2π) are π/3 and π.

8 0
3 years ago
I'm a little bit confused about how to approach this can someone help?
Taya2010 [7]

Answer:

4

Step-by-step explanation:

ΔABC is congruent with ΔDEF.  That means the corresponding sides are congruent.

Look at the order of the letters.  EF are the last two letters of ΔDEF.  So this corresponds with the last two letters of ΔABC.  Therefore, EF ≅ BC.

EF ≅ BC

x² + 8x = 48

x² + 8x − 48 = 0

(x + 12) (x − 4) = 0

x = -12 or 4

Since x can't be negative, x = 4.

5 0
3 years ago
Help please...........
ElenaW [278]
Parallel lines always have the same slope.  In fact that is the definition of parallel lines :P  (Technically they have the same slope and different y-intercepts, because parallel lines can never intersect...)

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7 0
2 years ago
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