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Shkiper50 [21]
3 years ago
5

Last week, Jen started a new job at the mall. She worked 36 hours over 4 workdays of equal length. She makes $8 an hour. How muc

h did she make for each day of work?
Mathematics
1 answer:
Anastaziya [24]3 years ago
3 0

Answer:

1652

Step-by-step explanation:

because 36x4=144 and 144x8=1652

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Jim’s football team started a play on the 50 yard line. On the first play, the team had a 7-yard gain. On the second play, they
Advocard [28]

Answer:

47 yard line

Step-by-step explanation:

50+7-10=47

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4 years ago
4. Membership in FFA is limited to youth who a. are in the country b. enroll in an agriscience program in school. c. plan career
shepuryov [24]

Answer:

it is B enroll in an ag. program in school.


Step-by-step explanation:


8 0
3 years ago
Find the sum.<br> 14 + 42 + 70 + ... + (28n − 14)
lions [1.4K]

Answer:

14n^2.

Step-by-step explanation:

This is Arithmetic with first term a =  14 and common difference d =  28.

Sum of n terms = n/2[2a + (n-1)d]

= n/2(28 +( n -1)28]

= n/2(28 + 28n - 28)

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5 0
2 years ago
Read 2 more answers
The sales of a grocery store had an average of $7,000 per day. The store introduced several advertising campaigns in order to in
Sati [7]

Answer:

a.The advertising campaigns increased the average daily sales.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the advertising campaigns increased the average daily sales.

Then, the null and alternative hypothesis are:

H_0: \mu=7000\\\\H_a:\mu> 7000

The significance level is 0.05.

The sample has a size n=100.

The sample mean is M=7280.

The standard deviation of the population is known and has a value of σ=1000.

We can calculate the standard error as:

\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1000}{\sqrt{100}}=100

Then, we can calculate the z-statistic as:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{7280-7000}{100}=\dfrac{280}{100}=2.8

This test is a right-tailed test, so the P-value for this test is calculated as:

\text{P-value}=P(z>2.8)=0.0026

As the P-value (0.0026) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the advertising campaigns increased the average daily sales.

7 0
3 years ago
WILL GIVE BRAINLIEST!!!!!!
ankoles [38]

Answer:

d??? i think

Step-by-step explanation:

4 0
3 years ago
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