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ANEK [815]
3 years ago
12

one half of the birds at the pet store are yellow. Tara buys one of the birds. Then one third of the birds at the pet store are

yellow. How many yellow birds were at the pet store before Tara bought one? explain how u know
Mathematics
1 answer:
Sati [7]3 years ago
7 0
Well, y=ny
2(y-1)=ny
(where ny is not-yellow)
You get y=2y-2 or y=2. You had two yellow birds and two other types.
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Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s
Nataliya [291]

Answer:

f(x)=\frac{1}{2}x^2-4x+5

Step-by-step explanation:

A parabola is written in the form

f(x)=a((x-h)^2+k) (1)

where:

h is the x-coordinate of the vertex of the parabola

ak is the y-coordinate of the vertex of the parabola

a is a scale factor

For the parabola in the problem, we know that the vertex has  coordinates (4,-3), so we have:

h=4 (2)

ak=-3

From this last equation, we get that a=\frac{-3}{k} (3)

Substituting (2) and (3) into (1) we get the new expression:

f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3 (4)

We also know that the parabola  contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6

So we also get:

a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}

So the equation of the parabola is:

f(x)=\frac{1}{2}((x-4)^2 -6) (5)

Now we want to rewrite it in the standard form, i.e. in the form

f(x)=ax^2+bx+c

To do that, we simply rewrite (5) expliciting the various terms, we find:

f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5

6 0
3 years ago
-3q + 12 greater than equal too 4q - 30 solve for q
valentina_108 [34]

Solving the inequality -3q+12\geq 4q-30 the value of q is q\leq 6

Step-by-step explanation:

We need to solve the inequality: -3q+12\geq 4q-30 and find value of q

Solving:

-3q+12\geq 4q-30\\Adding\,\,-12\,\,on\,\,both\,\,sides:\\-3q+12-12\geq 4q-30-12\\-3q\geq 4q-42\\Adding\,\,-4q\,\,on\,\,both\,\,sides:\\-3q-4q\geq 4q-42-4q\\-7q\geq -42\\Divide\,\,both\,\,sides\,\,by\,\,7\\\frac{-7q}{7}\geq \frac{-42}{7}\\ -q\geq -6\\Multiply\,\,both\,\,sides\,\,by\,\,-1\,\,and\,\,reverse\,\,the\,\,inequality:\\q\leq 6

So, solving the inequality -3q+12\geq 4q-30 the value of q is q\leq 6

Keywords: Solving inequality

Learn more about solving inequality at:

  • brainly.com/question/7490805
  • brainly.com/question/9590016
  • brainly.com/question/2840217

#learnwithBrainly

6 0
3 years ago
Consider the leading term of y = −2x2 − 3x + 3. What is the end behavior of the graph?
Tresset [83]
Y= -4 -3x +3 
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3 years ago
The cost to rent a car is $25 plus an additional $0.15 for each mile the car is driven. How many miles was a car driven if it ha
marissa [1.9K]
312

71.80-25.00= 46.80

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3 years ago
What is the square root of 53 rounded to the nearest hundreth
Temka [501]
7.28
hope i helped ya pal :3
8 0
3 years ago
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