Answer:
7088 m²
Step-by-step explanation:
The area of the half-cylinder is half the area of a cylinder with the same dimensions. This half-cylinder has a radius of 0.3 m and a length of 0.8 m, so its area is ...
A = πr(r +l) = π(0.3 m)(0.3 m+0.8 m) = 0.33π m² ≈ 1.0362 m²
The area of the bottom part of the box is the sum of its lateral area and its base area.
lateral area = Ph = (2(0.6m +0.8m))(0.75 m) = 2.1 m²
base area = lw = (0.8 m)(0.6 m) = 0.48 m²
The total area is then ...
total area = half-cylinder area + lateral area + base area
= 1.0362 m² +2.1 m² +0.48 m²
= 3.6162 m²
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The area for 1960 mailboxes will be 1960 times this area, or ...
area for week's production = 1960 × 3.6162 m² = 7087.752 m²
It will take about 7088 square meters of aluminum to make these mailboxes.
The answer would be three inches per year or B. Hope this helped :)
Answer:
Step-by-step explanation:
Total surface area = 2πr(r+h)
If the total area of the bigger cylinder is 400cm² and radius is 4cm, then;
400=2(3.14)(r)(r+4)
400= 6.26r(r+4)
400=100.48 + 25.12h
299.52 = 25.12h
H = 299.52/25.12
H = 11.92cm
For the smaller cylinder
The height is calculated as;
H/h = R/r
11/92/
