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Aneli [31]
3 years ago
15

What's 12 5/8-7 2/5=

Mathematics
1 answer:
pickupchik [31]3 years ago
7 0
That would be 5 9/40
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Brainliest for correct answer<br><br> A. 2<br><br> B. -2<br><br> C. 1/2<br><br> D. -1/2
seropon [69]

Answer:

B) -2

Step-by-step explanation:

I got the slope by using two points on the line (0,7) and (4,-1)

Slope=y2-y1/x2-x1

(7--1)/(0-4)

=

8/-4

I then simplified 8/-4 to -2

You could also solve by finding the rise over run for two points on the line.

The rise is 2 and the run is -1, making it 2/-1 or -2

8 0
3 years ago
Read 2 more answers
Three (3) is a common factor of 21 and 22.<br> O A. True<br> B. False<br> SUBMIT
Svetradugi [14.3K]

Answer:

false.

Step-by-step explanation:

Factors for 21: 1, 3, 7, and 21. Factors for 22: 1, 2, 11, and 22.

7 0
2 years ago
Read 2 more answers
Major league baseball salaries averaged $1.5 million with a standard deviation of $0.8 million in 1994. suppose a sample of 100
seropon [69]

Answer: The probability that the avg. salary of the 100 players exceeded $1 million is approximately 1.

Explanation:

Step 1: Estimate the standard error. Standard error can be calcualted by dividing the standard deviation by the square root of the sample size:

SE=\frac{0.8}{\sqrt{100}}=\frac{0.8}{10} = 0.08

So, Standard Error is 0.08 million or $80,000.

Step 2: Next, estimate the mean is how many standard errors below the population mean $1 million.

\frac{1 - 1.5}{0.08}

=-6.250

-6.250 means that $1 million is siz standard errors away from the mean. Since, the value is too far from the bell-shaped normal distribution curve that nearly 100% of the values are greater than it.

Therefore, we can say that because 100% values are greater than it, probability that the avg. salary of the 100 players exceeded $1 million is approximately 1.

5 0
3 years ago
What are the coordinates of the x-intercepts of the parabola y = x² - 8x + 15?
tamaranim1 [39]

Answer:

(3, 0) and (5, 0)

Step-by-step explanation:

we have

y=x^{2}-8x+15

we know that

The x-intercepts are the values of x when the value of y is equal to zero

so

For y=0

x^{2}-8x+15=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2}-8x+15=0  

so

a=1\\b=-8\\c=15

substitute in the formula

x=\frac{-(-8)\pm\sqrt{-8^{2}-4(1)(15)}} {2(1)}

x=\frac{8\pm\sqrt{4}} {2}

x=\frac{8\pm2} {2}

x=\frac{8+2} {2}=5

x=\frac{8-2} {2}=3

so

x=3, x=5

therefore

The x-intercepts are (3,0) and (5,0)

4 0
3 years ago
Factor the polynomial. 7x2 + 68xy - 20y2 A) (7x - 2y)(x + 10y) B) (7x - 10y)(x - 2y) C) (7x + 10y)(x + 2y) D) (7x + 2y)(x - 10y)
Otrada [13]
For this case we have the following polynomial:
 7x2 + 68xy - 20y2
 Factoring we have:
 (7x-2y) (x + 10y)
 We verify the factorization:
 7x2 + 70xy - 2xy - 20y2
 Rewriting we have:
 7x2 + 68xy - 20y2
 Therefore, the factorization is correct.
 Answer:
 
A) (7x - 2y) (x + 10y)
5 0
3 years ago
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