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2 years ago

The square pqrs is shown.

Mathematics

1 answer:

ira [324]2 years ago

5 0

Answer:

1:1

Step-by-step explanation:

The ratio would be 1:1 since it's a square, the sides will always be the same. In a square ,all sides are the same length. If they are not, then it wouldn't be a square.

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3x+2 less or equal to 8

bearhunter [10]

Answer:

less than

Step-by-step explanation:

x = 0(number of pictures) 3 * 0 = 0

0 is less than 8 :)

6 0

3 years ago

I don't get how to solve it

skelet666 [1.2K]

I don't know for a fact but I think k=1.125

8 0

3 years ago

What is the equation of the following line written in slope intercept form? (-5,-1)

solmaris [256]

Answer:

$\large\boxed{y=-\dfrac{2}{3}x-\dfrac{13}{3}}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

From the graph we have two points (-5, -1) and (-2, -3).

Look at the picture.

Calculate the slope:

$m=\dfrac{-3-(-1)}{-2-(-5)}=\dfrac{-2}{3}=-\dfrac{2}{3}$

Put it to the equation in slope-intercept form:

$y=-\dfrac{2}{3}x+b$

We can't read the y-intercept from the graph. Therefore put the coordinates of the point (-5, -1) to the equation and calculate b:

$-1=-\dfrac{2}{3}(-5)+b$

$-1=\dfrac{10}{3}+b$ subtract 10/3 from both sides

$-\dfrac{3}{3}-\dfrac{10}{3}=b\to b=-\dfrac{13}{3}$

Finally:

$y=-\dfrac{2}{3}x-\dfrac{13}{3}$

4 0

3 years ago

Question 3 of 10

Bas_tet [7]

Answer:

A. $y-5=1.5(x-4)$ .

B. $y=1.5x-1$ .

Step-by-step explanation:

The given line passes through (2,2) and (4,5).

The slope the given line can be found using the formula;

$m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{5-2}{4-2}$

This gives $m=\frac{3}{2}=1.5$ .

The slope-intercept form is $y-y_1=m(x-x_1)$ .

We substitute the second point to get:

$y-5=1.5(x-4)$ .

We expand to get:

$y-5=1.5x-6$ .

$y=1.5x-6+5$ .

$y=1.5x-1$ .

4 0

3 years ago

A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between

sattari [20]

Answer:

$B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)$

b) 0.09

Step-by-step explanation:

We are given the following in the question:

$B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)$

where B(t) gives the brightness of the star at time t, where t is measured in days.

a) rate of change of the brightness after t days.

$B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(t) = 0.45\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\times \dfrac{2\pi}{4.4}\\\\B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)$

b) rate of increase after one day.

We put t = 1

$B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(1) = \dfrac{0.9\pi}{4.4}\bigg(\cos(\dfrac{2\pi (1)}{4.4}\bigg)\\\\B'(t) = 0.09145\\B'(t) \approx 0.09$

The rate of increase after 1 day is 0.09

8 0

3 years ago