Is x^4 +400 a complex conjugate

What is the sum of 2/11’ 2/7’ and 1/11’?

pav-90 [236]

Solution

To solve this addition of fractions we are gonna apply the fraction rule which is;

a/c + b/c = (a + b)/c

2/11 + 1/11 = (2 + 1)/11

= (2 + 1)/11 + 2/7

Now add the numerators 2 + 1

= (2 + 1)/11 + 2/7

= 3/11 + 2/7

Now we find the least common multiple

The least common multiple of 11 and 7 is 77.

But before that we cross multiply the numerators.

3 * 7 = 21
2 * 11 = 22

Now the ajustes fraction is;

21/77 + 22/77

Apply the fraction rule which is;

a/c + b/c = (a + b)/c

= (21 + 22)/77

Now we add the numerators.

43/77

Therefore the answer in fraction is 43/77 and in decimal form it is 0.55841

6 0

3 years ago

6.5 + (−2) + 10.5 I could probably do this but its kind of hard to understand. Explain?

elena-s [515]

Hello! Let's work this problem from left to right to make things a bit easier ;)

6.5+(-2) is the same as 6.5-2, since adding a negative is the same as subtracting a positive. 6.5-2=4.5

Now, we have to add 10.5 to 4.5, which gives us the grand total of 15. I hope this helped! Let me know if you need anything else!

6 0

3 years ago

Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t

Svet_ta [14]

Answer:

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

$T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}$

$[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

$T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}$

$[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]$

Finally, the third vector of basis E is $e3(t)=t^{2}$

$T[e3(t)]=T(t^{2})$

in the equation : a2 = 1

$T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}$

Then

$[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]$

And that is the third column of [T]EE

Let's write our matrix

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

$X=\left[\begin{array}{c}1&0&0\\\end{array}\right]$

$AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

Applying the coordinates 2,6 and -2 to the basis E we obtain

$2+6t-2t^{2}$

That was the original result of T[e1(t)]

8 0

3 years ago

-3z+8=2z-12 what is the answer?

Gre4nikov [31]

Answer:

Step-by-step explanation:

Simplifying

-3a + 8 = 2z + -12

Reorder the terms:

8 + -3a = 2z + -12

Reorder the terms:

8 + -3a = -12 + 2z

Solving

8 + -3a = -12 + 2z

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-8' to each side of the equation.

8 + -8 + -3a = -12 + -8 + 2z

Combine like terms: 8 + -8 = 0

0 + -3a = -12 + -8 + 2z

-3a = -12 + -8 + 2z

Combine like terms: -12 + -8 = -20

-3a = -20 + 2z

Divide each side by '-3'.

a = 6.666666667 + -0.6666666667z

Simplifying

a = 6.666666667 + -0.6666666667z

3 0

3 years ago

Read 2 more answers

The sum of twice a number and seven is twenty five

Mama L [17]

9

Because 9x2 is 18+7=25

3 0

3 years ago