You can model an arch at your school using the equation $y=-0.5\left(x+4\right)\left(x-4\right)$ , where $x$ and $y$ are measure
1 answer:
Answer:
8feet
Step-by-step explanation:
Given the equation that models the arch of a school expressed as;
If the x axis represents the ground;
At the ground level, x = 0
Substitute x = 0 into the equation to get y;
y = -0.5(0+4)(0-4)
y = -0.5(4)(-4)
y = -0.5 * -16
y = 8ft
Hence the y axis at the ground level is 8feet
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Answer:
B.
Step-by-step explanation:
First, let's start from the parent function. The parent function is:
The possible transformations are so:
,
where a is the vertical stretch, b is the horizontal stretch, c is the horizontal shift and d is the vertical shift.
From the given equation, we can see that a=1 (so no change), b=3, c=-3 (<em>negative </em>3), and d=3.
Thus, this is a horizontal stretch by a factor of 3, a shift of 3 to the <em>left </em>(because it's negative), and a vertical shift of 3 upwards (because it's positive).