You can model an arch at your school using the equation $y=-0.5\left(x+4\right)\left(x-4\right)$ , where $x$ and $y$ are measure
d in feet. The x-axis represents the ground. Find the width of the arch at ground level.
1 answer:
Answer:
8feet
Step-by-step explanation:
Given the equation that models the arch of a school expressed as;
If the x axis represents the ground;
At the ground level, x = 0
Substitute x = 0 into the equation to get y;
y = -0.5(0+4)(0-4)
y = -0.5(4)(-4)
y = -0.5 * -16
y = 8ft
Hence the y axis at the ground level is 8feet
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72% = 72/100
72/100=36/50=18/25
You can use the pythagoras theorem.
20^2=5^2+x^2
x^2=400-25
x^2=375
x = 19.36
20-19.36=0.64 feet
The answer is 0.64 feet :)
Answer:
B
it's a recurring number therefore it's irrational
Answer:
Im bored wanna talk?
Step-by-step explanation:
32 ounces is 2 pounds so simple math 3+2=5 si your answer is 5 pounds