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frez [133]
3 years ago
11

Adina read 60 out of 100 pages in a comic book.Write the fraction of the pages she read in simplest form

Mathematics
1 answer:
Ad libitum [116K]3 years ago
8 0

Answer:

3/5 is 60/100 in it's simplest form.

Step-by-step explanation:

60 divided by 20 is 3 and 100 divided by 20 is 5.

So 3/5

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3-2/3= ?<br><br><br> 2/3 is half
Helga [31]
Exact form = 7/3

Decimal = 2.3

Mixed number Form = 2 1/3
8 0
3 years ago
If 1/4 gallons of water are enough to fill 7/10 of the pool how much water is nessacary to fill in the entire pool
anyanavicka [17]
<h3>Answer:  5/14 gallons</h3>

============================================================

Work Shown:

1/4 = 0.25

7/10 = 0.70 = 70%

We are told that 0.25 gallons of water fills 70% of the pool

We want to find how many gallons of water (call it x) are needed to fill 100% of the pool.

Set up the proportion below and solve for x

(0.25 gallons)/(70% filled) = (x gallons)/(100% filled)

0.25/70 = x/100

0.25*100 = 70x ....... cross multiply

25 = 70x

70x = 25

x = 25/70

x = (5*5)/(5*14)

x = 5/14 gallons

----------------------------------------

An alternate method:

1/4 gallons = 7/10 pools filled

(10/7)*(1/4 gallons) = (10/7)*(7/10 pools filled)

(10*1)/(7*4) gallons = (10*7)/(7*10) pools filled

10/28 gallons = 1 pool filled

(5*2)/(14*2) gallons = 1 pool filled

5/14 gallons = 1 pool filled

In the second step, I multiplied both sides by 10/7 so that the "7/10" turns into "1".

----------------------------------------

Yet another alternate method:

1/4 = 10/40

7/10 = 28/40

We need 10/40 gallons of water to fill 28/40 of one pool. We can multiply both fractions by 40 to indicate that 10 gallons of water will fill up 28 pools.

So we have this ratio

10 gallons : 28 pools

Dividing both parts by 28 tells us how many gallons are needed for one pool

10 gallons : 28 pools

10/28 gallons : 28/28 pools

10/28 gallons : 1 pool

5/14 gallons : 1 pool

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Answer: A. its basically symmetry

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Step-by-step explanation:

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Answer:  The required product is 10x^2-y^2+3xy+6x+3y.

Step-by-step explanation:  We are to find the product f the following two algebraic expressions:

E_1=2x+y,\\\\E_2=5x-y+3.

To find the product of the above two expressions, we must multiply each term of the first expression with each term of the second expression.

The multiplication is as follows:

M\\\\=E_1 \times E_2\\\\=(2x+y)\times(5x-y+3)\\\\=10x^2-2xy+6x+5xy-y^2+3y\\\\=10x^2-y^2+3xy+6x+3y.

Thus, the required product is 10x^2-y^2+3xy+6x+3y.

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