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The volume of this cylinder is 1,909.92384 cubic millimeters. What is the radius? Use n=3.14 and round your answer to the neares

klemol [59]

Remember that the volume of a cylinder is

$\begin{gathered} V=\pi\cdot r^2\cdot h \\ \end{gathered}$

so we have that

$r=\sqrt[]{\frac{V}{\pi\cdot h}}=\sqrt[]{\frac{1909.92384}{3.14\cdot6.6}}=\sqrt[]{92.12}=9.6$

so the radius is 9.6 milimeters

6 0

1 year ago

What is the answer to 78.2÷7<br>

Lesechka [4]

Answer:

11.1714

Step-by-step explanation:

Just use a calculator! :)

3 0

3 years ago

Read 2 more answers

Johnson’s Hardware randomly selects 125 of its customers and questions them to determine their overall customer satisfaction rat

Sphinxa [80]

Answer:

a. 92%

b. 4425

Step-by-step explanation:

So there are 5000 customers in total, and 100 were completely satisfied, and 15 were satisfied and 10 weren't satisfied a bit. so 100+15 is 115 so 115 people in total were satisfied out of 125 because there were 125, and 115+10 is 125 anyways. So 115/125 is .92, and you can convert that into a percentage, 92% of the 250 customers were satisfied so then 250*5 is 5000, so then just multiply 115 by 5 as well. You get 575. So 575 were satisfied out of the 5000 customers and 5000-575 are the people not satisfied, so 4425.

probably wrong because it doesnt sound right but just try it

4 0

3 years ago

The standard deviation of math test scores at one high school is 16.1. A teacher claims that the standard deviation of the girls

Elanso [62]

Answer:

$\chi^2 =\frac{22-1}{259.21} 166.41 =13.482$

$p_v =P(\chi^2$

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(13.482,21,TRUE)"

If we compare the p value and the significance level provided we see that $p_v >\alpha$ so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population deviation is not significantly lower than 16.1 at 1% of significance.

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

$n=22$ represent the sample size

$\alpha=0.01$ represent the confidence level

$s^2 =12.9^2=166.41$ represent the sample variance obtained

$\sigma^2_0 =16.1^2 =259.21$ represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population deviation is smaller than 16.1 (that's equivalent to check if the population variance is lower than 259.21:

Null Hypothesis: $\sigma^2 \geq 259.21$

Alternative hypothesis: $\sigma^2$

Calculate the statistic

For this test we can use the following statistic:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

$\chi^2 =\frac{22-1}{259.21} 166.41 =13.482$

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case 21. And since is a left tailed test the p value would be given by:

$p_v =P(\chi^2$

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(13.482,21,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that $p_v >\alpha$ so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population deviation is not significantly lower than 16.1 at 1% of significance.

3 0

4 years ago

What's the square of the quantity of 18 less than x

Zigmanuir [339]

(18 - x)^2

If (a - b)^2 then the answer is a^2 - 2ab + b^2

18^2 - 36x + x^2

The answer is x^2 - 36x + 324

8 0

3 years ago