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Answer:
9) x=58
10) r=4
11) m=4
12) p=3
13) x=6
14) x=-3
15) s=400
Step-by-step explanation:
9) x+2/5=12
x5 x5
x+2=60
-2 -2
x=58
10) 7r + 14 - 3r =30
-14 -14
<u>7r-3r</u>=16
4r=16
÷4 ÷4
r=4
11) m+2=6
-2 -2
m=4
÷ ÷
m=4
12) <u>2</u>(5p+9)=48
10p+18=48
-18 -18
10p=30
÷10 ÷10
p=3
13) <u>5</u>(2x-8)=20
10x-40=20
+40 +40
10x=60
÷10 ÷10
x=6
14)<u>6</u>(3-2x)=54
18-12x=54
-18 -18
-12x=36
÷-12 ÷-12
x=-3
15) -
=40
x5 x5
2s-=200
x2 x2
<u>2s-1s</u>=400
1s=400
÷1 ÷1
s=400
Answer:
a. f(n) = n(n+1)/2
b. 351
c. 19
d. no; n would not be an integer for f(n) = 17.
Step-by-step explanation:
a. The terms are 1, 3, 6, 10, ...
Each term has the term number added to the previous term. That is, first differences are 3-1 = 2, 6-3 = 3, 10-6 = 4. These differences have a constant difference of 1.
When the 2nd differences are constant, a 2nd degree polynomial can describe the sequence. It is a little bit of trouble to find that polynomial.
For the polynomial ...
We can substitute values for n and f(n) to get 3 equations in 3 unknowns:
Solving these equations by your favorite method gives ...
(a, b, c) = (1/2, 1/2, 0)
That is, the function representing the relationship is ...
f(n) = n(n+1)/2 . . . . the function describing the relationship
__
b. f(26) = 26(27) = 13(27) = 351 . . . . the number of squares in term 26
__
c. The number of the term having 190 squares can be found by solving ...
n(n +1)/2 = 190
n(n +1) = 380 = 19(20)
The 19th term will have 190 squares.
__
d. Terms 5 and 6 are 15 and 21.
17 is not the value of one of the terms in this sequence.