3 years ago

Help please this is my last hope

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

7 0

Answer:

????

Step-by-step explanation:

You might be interested in

FAST HELP IS NEEDED PLZ!! What are the roots of the equation? x2+24=14x

Shkiper50 [21]

16x and 24 are the Roots to your Question!

Hope This Helps!

8 0

4 years ago

Read 2 more answers

Whoever reads this I hope you have a great day and don't forget to smile :) #spread positivity

svetlana [45]

Answer: ty! I hope you do too ✨

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Factor the problem x^2-6x+9

koban [17]

The answer will be (x - 3)^2

7 0

3 years ago

Read 2 more answers

A study was conducted to determine whether there were significant differences between medical students admitted through special

Mekhanik [1.2K]

Answer:

$P(X\geq 9)=P(X=9)+P(X=10)$

And using the probability mass function we got:

$P(X=9)=(10C9)(0.913)^9 (1-0.913)^{10-9}=0.383$

$P(X=10)=(10C10)(0.913)^{10} (1-0.913)^{10-10}=0.402$

And replacing we got:

$P(X \geq 9) = 0.383 +0.402= 0.785$

Step-by-step explanation:

Let X the random variable of interest "number of students graduated", on this case we now that:

$X \sim Binom(n=10, p=0.913)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We want to find the following probability:

$P(X\geq 9)=P(X=9)+P(X=10)$

And using the probability mass function we got:

$P(X=9)=(10C9)(0.913)^9 (1-0.913)^{10-9}=0.383$

$P(X=10)=(10C10)(0.913)^{10} (1-0.913)^{10-10}=0.402$

And replacing we got:

$P(X \geq 9) = 0.383 +0.402= 0.785$

3 0

4 years ago

How many cars averaged less than 30 miles per gallon? 75 20 55 70

LekaFEV [45]

Your answer is 75, hope this helps you!

5 0

3 years ago

Read 2 more answers