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kirill [66]
3 years ago
11

Help please this is my last hope

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
7 0

Answer:

????

Step-by-step explanation:

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What is the smallest number that can be added to 1923 to make the answer divisible by 9?
Stolb23 [73]

Answer:

3

Step-by-step explanation:

1926/9=214

1923+3=1926

7 0
3 years ago
WILL GIVE BRAINLIEST WHAT IS THE FORMULA FOR SURFACE AREA
eimsori [14]

Answer:

Hi! The formula for surface area is:

area = 2lw + 2lh + 2hw

(l = length, w = width, h = height.)

<em>Hope this helps! :)</em>

8 0
3 years ago
Read 2 more answers
I need help ASAP (20points)
Leto [7]

y = x^2 + 2x...eqn 1

y = 3x + 20...eqn 2

subst for y in eqn 1...

=> x^2 +2x = 3x +20

=> x^2 - x - 20 =0

=> (x-5) (x+4) =0

=> x = 5 or -4

for x =5, y = 35 (sub for x in eqn 1 or 2)

for x = -4, y = 8 (sub for x in eqn 1 or 2)

5 0
3 years ago
An investigator wants to estimate caffeine consumption in high school students. how many students would be required to estimate
astraxan [27]

We can solve this problem by referring to the standard probability distribution tables for z.

We are required to find for the number of samples given the proportion (P = 5% = 0.05) and confidence level of 95%. This would give a value of z equivalent to:

z = 1.96

Since the problem states that it should be within the true proportion then p = 0.5

Now we can find for the sample size using the formula:

n = (z^2) p q /E^2

where,

<span> p = 0.5</span>

q = 1 – p = 0.5

E = estimate of 5% = 0.05

Substituting:

n = (1.96^2) 0.5 * 0.5 / 0.05^2

n = 384.16

<span>Around 385students are required.</span>

6 0
3 years ago
Help with num 9 please. thanks​
Alik [6]

Answer:

See Below.

Step-by-step explanation:

We want to show that the function:

f(x) = e^x - e^{-x}

Increases for all values of <em>x</em>.

A function is increasing whenever its derivative is positive.

So, find the derivative of our function:

\displaystyle f'(x) = \frac{d}{dx}\left[e^x - e^{-x}\right]

Differentiate:

\displaystyle f'(x) = e^x - (-e^{-x})

Simplify:

f'(x) = e^x+e^{-x}

Since eˣ is always greater than zero and e⁻ˣ is also always greater than zero, f'(x) is always positive. Hence, the original function increases for all values of <em>x.</em>

8 0
3 years ago
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