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OLga [1]
3 years ago
11

**A Punnett square should be used to find each answer.**

Biology
1 answer:
KatRina [158]3 years ago
8 0

Answer:

100%

100%

50%

100%

75%

Explanation:

dont use the exact words so u can avoid plagerism lol

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The size and shape of what can reveal climate?
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The part of the cell that can be stimulated by outside chemicals, triggering the cell to
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Answer:

A

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8 0
2 years ago
Which of these pairs of body structures BEST illustrates a homologous relationship?
Rashid [163]
<span>A) Leg of a horse and the leg of a dog.
The rest of the choices are examples of convergent evolution because they are similar in  structures that evolved in separate places in the animal kingdom.
>Bats are mammals and birds are not, yet they both evolved a similar appendage</span><span>
Choices to this question are:
A) the leg of a horse and the leg of a dog
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4 0
4 years ago
Organisms with the genotypes aabbccdd and aabbccdd are crossed. What are the expected proportions of the following progeny?
Dvinal [7]

Answer:

a) \frac{27}{64}

b)\frac{1}{32}

c) \frac{27}{64}

d) \frac{3}{64}

Explanation:

The correct question is

Organisms with the genotypes AABbCcDd and AaBbCcDd are crossed. What are the expected proportions of the following progeny?

a. A_B_C_D_

b. AabbCcDd

c. a phenotype identical to either parent

d. A_B_ccdd

Solution

In such question the probability for each allele pair is to be determines separately

For instance,

AA * Aa will produce AA, Aa, AA, Aa this means that all the the probability of getting both AA and Aa is \frac{1}{2}

Like wise when Bb and Bb are crossed, BB, Bb, Bb, and bb are produced. So the probability of getting dominant trait i.e BB or Bb is \frac{3}{4} and recessive trait i.e bb is \frac{1}{4}

Chance to get homozygous bb only or BB only is \frac{1}{4}

and chance of getting Bb is  \frac{1}{2}

Like Bb and Bb cross, the same will be the probabilities for Cc and Cc cross and Dd and Dd cross

Part A)

\frac{1}{4} * \frac{3}{4} * \frac{3}{4} * \frac{3}{4} \\= \frac{27}{64}

Part B)

\frac{1}{4} * \frac{1}{2} *  \frac{1}{2}*  \frac{1}{2}\\=  \frac{1}{32}

Part C)

\frac{1}{4} * \frac{3}{4} * \frac{3}{4} * \frac{3}{4} \\= \frac{27}{64}

Part D)

\frac{3}{4} * \frac{1}{4} * \frac{1}{4} * \frac{1}{4} \\= \frac{3}{64}

5 0
3 years ago
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