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scoundrel [369]
3 years ago
7

Expand and simplify 1: (2 ) a) 9( 3 – 10n ) -3 ( 10n + 1 )

Mathematics
1 answer:
Lerok [7]3 years ago
4 0

Answer:

Hope it can help you .......

Mark me as a brainlist and follow me.....

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What is the vertex of the graph of this function<br> y= -(x+2) (x+4)
Shkiper50 [21]

Answer:

y=-(x+2)(x+4)

y=-(x^2+4x+2x+8)

y=-(x^2+6x+8)

y=-(x^2+4x+2x+8)

Y=-x(x+4)+2(x+4)

y=-(x+2)(X+4)

So vertex is (2,4)

4 0
4 years ago
Question what is the answer<br> -2(4-3p)=24
erik [133]
P= 16 over 3 this is the straight forward answer
7 0
3 years ago
Segment CD is given with vertices C(a,b) and D(2a,b). Find the length of segment C'D', the image of segment CD after a dilation
artcher [175]
The dilation is a scale factor of 2, that is:

C'D' = 2(CD)

the length of CD is given by:
CD = √( (a - 2a)^2 + (b - b)^2 )

<span>CD = √(a^2) = a
</span>
hence the new segment is 2a long.
7 0
4 years ago
In the diagram of a circle shown below, m AC = 89° and m BC = 153°. Determine m∠ACB.
timama [110]

Answer:

The measure of the angle ACB is 59°.

Step-by-step explanation:

Let be D the location of the center of circle and r is the radius of the figure, the triangles ACD and BCD are isosceles triangles, since AD = CD = BD = r. And the measure of the angle C associated with each triangle are, respectively:

Triangle ACD

m\angle C = \frac{180^{\circ}-89^{\circ}}{2}

m\angle C = 45.5^{\circ}

Triangle BCD

m \angle C = \frac{180^{\circ}-153^{\circ}}{2}

m\angle C = 13.5^{\circ}

Lastly, the measure of the angle ACB is:

m\angle ACB = 45.5^{\circ} + 13.5^{\circ}

m\angle ACB = 59^{\circ}

The measure of the angle ACB is 59°.

6 0
3 years ago
Solve the equation<br> cb – 20 = –10 for b.
Ymorist [56]
ANSWER: B = 10/C
You have to isolate the variable by dividing each side by factors that don’t contain the variable
3 0
3 years ago
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