Segment CD is given with vertices C(a,b) and D(2a,b). Find the length of segment C'D', the image of segment CD after a dilation
with a scale factor of 2.
1 answer:
The dilation is a scale factor of 2, that is:
C'D' = 2(CD)
the length of CD is given by:
CD = √( (a - 2a)^2 + (b - b)^2 )
<span>CD = √(a^2) = a
</span>
hence the new segment is 2a long.
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