This is not a multiple choice, I need your help!

Mathematics

2 answers:

77julia77 [94]3 years ago

7 0

Answer:

Trapezoid, E, is the correct answer.

nikitadnepr [17]3 years ago

6 0

Answer:

All of them because its four sides which is a quadrilateral and all of the above shapes have four sides

Step-by-step explanation:

You might be interested in

Which of the following has a value of 84? A. 512 B. 4,096 C. 32 D. 83

andreev551 [17]

Answer is B. 4,096

I encountered this problem before. This is a trick question.
84 is not really the number 84. It is 8 raised to the 4th power.

So 8⁴ is equal to 4,096.

8 x 8 x 8 x 8 = 4,096

8 x 8 = 64
64 x 8 = 512
512 x 8 = 4,096

6 0

3 years ago

If find the values of x and y.

uysha [10]

5-2=3 so x is equal to 3
-3+10 is equal to 7 so y is equal to 10
With this we can conclude that x=3 and y=10
I hope that helps :)

8 0

2 years ago

6x^2y^3/3xy 6x squared times y cubed divided by 3xy simplify

Lera25 [3.4K]

Answer:

$2xy^2$

Step-by-step explanation:

The question is:

$\frac{6x^{2}y^3}{3xy}$

"6" and "3" cancels out as well as the "x"s and "y"s. Shown below:

$\frac{6x^{2}y^3}{3xy}\\=2xy^2$

4 0

3 years ago

A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a stand

Art [367]

Answer:

b. Mean = 1.6 years, standard deviation - 0.92 years, shape: approximately Normal.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction of normal Variables:

When we subtract normal variables, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a standard deviation of 4.2 years. Sample of 35:

This means that:

$\mu_G = 15$