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Liono4ka [1.6K]
3 years ago
5

Find an equation of the line that passes through (-5,-7) and is parallel to 5x+9y+18=0. Give answer in slope intercept form

Mathematics
1 answer:
Kipish [7]3 years ago
5 0

Answer:

y = - \frac{5}{9} x - \frac{88}{9}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 5x + 9y + 18 = 0 into slope- intercept form

Subtract 5x + 18 from both sides

9y = - 5x - 18 ( divide all terms by 9 )

y = - \frac{5}{9} x - 2 ← in slope- intercept form

with m = - \frac{5}{9}

Parallel lines have equal slopes, thus

y = - \frac{5}{9} x + c ← is the partial equation

To find c substitute (- 5, - 7) into the partial equation

- 7 = \frac{25}{9} + c ⇒ c = - 7 - \frac{25}{9} = - \frac{88}{9}

y = - \frac{5}{9} x - \frac{88}{9} ← equation of line

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