576 cm you were times 2304×4 after doing all the multiplication you would get 576 cm
So if the measure of angle AMB = 90 so the another right triangle is formed which is ADM, since the it is a right triangle the legs are equal, then the lenght AD = DM and we can solve the length of AM
AM = sqrt( AD^2 + DM^2)
AM = sqrt( 6^2 + 6^2)
AM = 6sqrt(2)
now we can solve the length of AB
AB = sqrt ( AM^2 + MB^2)
AB = sqrt ( 6sqrt(2)^2 + 6sqrt(2)^2)
AB = 12
so the perimeter = 2(6) + 2(12) = 36
Answer:
a)
b)
c)
d)
Step-by-step explanation:
We will use the following trigonometric identities
.
Recall that given a right triangle, the sin(theta) is defined by opposite side/hypotenuse. Since we know that the angle is in quadrant 2, we know that x should be a negative number. We will use pythagoras theorem to find out the value of x. We have that
which implies that . Recall that cos(theta) is defined by adjacent side/hypotenuse. So, we know that the hypotenuse is 7, then
b)Recall that , then using the identity from above, we have that
c) Recall that . Then,
d) Recall that and . Then
The questions asks for the domain of [f/g](x).
That is f(x) / g(x) = [x^2 - 25] / [X-5].
The domain of that functions are all the real except those where the denominator becomes zero.
You find those points by doing X - 5 = 0 => x = 5.
Then, the domain of [f/g](x) is all real numbers except x = 5.