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Irina-Kira [14]
4 years ago
15

If y2 = x3 + 2, which statement is true? The equation is a function at all values of x. The equation is not a function. The equa

tion is a function only when x < 0. The equation is a function only when x > 0.
Mathematics
1 answer:
tatyana61 [14]4 years ago
6 0

Answer:

The equation is not a function.

Step-by-step explanation:

We are given that

y^2=x^3+2

y=\pm\sqrt{x^3+2}

Function: It is mapping between the values of two sets A and B.

Each element of A has unique value in set B.

By definition of  function

In given function

y has no unique value for each value of x.

Substitute x=0

y=\pm \sqrt{0+2}=\pm \sqrt 2

Hence, it is not a function.

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stiks02 [169]

Answer:

C because its the only one that fits the question its asking. 12-6 8-4 4-2

Step-by-step explanation:

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3 years ago
Please I need help ASAP
andrezito [222]

I think the answer is 0.62

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3 years ago
A computer program has a bug that causes it to fail once in every thousand runs, on average. In an effort to find the bug, indep
Serhud [2]

Answer:

The standard deviation of the number of runs required is 2447.26

Step-by-step explanation:

For each run, there are only two possible outcomes. Either the program fails, or it does not. The probability of the computer failing during a run is independent of other runs. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The standard deviation for the expected number of trials for r sucesses is:

\sqrt{V(X)} = \sqrt{\frac{r(1-p)}{p^{2}}}

A computer program has a bug that causes it to fail once in every thousand runs, on average.

This means that p = \frac{1}{1000} = 0.001

In an effort to find the bug, independent runs of the program will be made until the program has failed six times. What is the standard deviation of the number of runs required?

This means that r = 6. So

\sqrt{V(X)} = \sqrt{\frac{6*0.999}{(0.001)^{2}}} = 2447.26

The standard deviation of the number of runs required is 2447.26

8 0
3 years ago
Would anyone care to explain how to get through this problem in the photo? I'm at a complete dead end! Any help would be appreci
shutvik [7]

Step-by-step explanation:

The slope of the equation tangent to y = f(x) at x = 4 is equal to f'(4). Therefore,

m = f'(4) = \dfrac{1}{(4)^2 - 9} = \dfrac{1}{7}

We also know that the line passes through the tangent point at (4, -1) so we can write the slope-intercept form of the equation as

y = mx + b \Rightarrow -1 = \dfrac{1}{7}(4) + b or

b = -\dfrac{11}{7}

so our equation is

y = \dfrac{1}{7}x -\dfrac{11}{7}

or in standard form,

x - 7y = 11

5 0
3 years ago
In a study of 420,095 Danish cell phone users, 135 subjects developed cancer of the brain or nervous system (based on data from
Maksim231197 [3]

Answer:

z=\frac{0.0003214 -0.00034}{\sqrt{\frac{0.00034(1-0.00034)}{420095}}}=-0.654  

p_v =2*P(Z  

So the p value obtained was a very high value and using the significance level given \alpha=0.005 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that the true proportion not differs significantly from the specified value of 0.00034 or 0.034%.

Step-by-step explanation:

1) Data given and notation  

n=420095 represent the random sample taken

X=135 represent the subjects developed cancer of the brain or nervous system (based on data from the Journal of the National Cancer Institute as reported in USA Today)

\hat p=\frac{135}{420095}=0.0003214 estimated proportion of subjects developed cancer of the brain or nervous system (based on data from the Journal of the National Cancer Institute as reported in USA Today)

p_o=0.00034 is the value that we want to test

\alpha=0.005 represent the significance level

Confidence=99.5% or 0.995

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the brain or nervous system at a rate that is different from the rate of 0.0340% :  

Null hypothesis:p=0.00034  

Alternative hypothesis:p \neq 0.00034  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.0003214 -0.00034}{\sqrt{\frac{0.00034(1-0.00034)}{420095}}}=-0.654  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.005. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z  

So the p value obtained was a very high value and using the significance level given \alpha=0.005 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that the true proportion not differs significantly from the specified value of 0.00034 or 0.034%.  

4 0
3 years ago
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