Given:
The given digits are 1,2,3,4,5, and 6.
To find:
The number of 5-digit even numbers that can be formed by using the given digits (if repetition is allowed).
Solution:
To form an even number, we need multiples of 2 at ones place.
In the given digits 2,4,6 are even number. So, the possible ways for the ones place is 3.
We have six given digits and repetition is allowed. So, the number of possible ways for each of the remaining four places is 6.
Total number of ways to form a 5 digit even number is:
Therefore, total 3888 five-digit even numbers can be formed by using the given digits if repetition is allowed.
Answer:
2) 11
3) 21
4) 7
Step-by-step explanation:
2) (-6) -(-17) = 17 - 6 = 11
3) 19 - (-2) = 19 + 2 = 21
4) (-13) + 20 = 20 - 13 = 7
59.96.
If you distribute 4 to 14.99 then you get the answer above.
Answer:
is a multiple of 4
Step-by-step explanation:
Let's think about this.
Even numbers are basically numbers that, when divided by 2, get us an integer.
This means that must be an even integer.
<em>However,</em>
Every other even number, when divided by 2, gets you an odd integer.
This means that every second even number, 
gets us an even number.
This also means that every time is an even number, n will be a multiple of 4 (as 
).
Test this out with any even number that's a multiple of 4 (all multiples of 4 are even numbers)
Hope this helped!
Answer:
Step-by-step explanation:
Given
Required
Determine the probability before the request of past experience
In this case, we only consider the 50 50 chance probability
