Answer:
14units
Step-by-step explanation:
Let the vertices of a rectangle be A(3, 1), B(3, 5), C(6, 5), and D(6, 1).
Using the formula for calculating distance between two points;
AB =√(5-1)²+(3-3)²
AB = √4²
AB = 4
BC = √(5-5)²+(6-3)²
BC = √3²
BC =>3
CD = √(1-5)²+(6-6)²
CD = √(-4)²
CD = √16
CD = 4
AD= √(1-1)²+(6-3)²
AD = √3²
AD = √9
AD =3
Perimeter of the rectangle = AB+BC+BD+AD
Perimeter of the rectangle = 4+3+4+3
Perimeter of the rectangle = 14units
I believe it’s m=3 b=4 I don’t understand really so I think this is my answer
Answer:
<u>a</u>
Step-by-step explanation:
Given :
⇒ P (Sumit) = 1/2
⇒ P (Sujan) = 1/3
⇒ P (Rakesh) = 1/a
⇒ P (total) = 3/4
============================================================
Solving :
⇒ 1/2 × 1/3 × 1/a = 3/4
⇒ 1/6 × 1/a = 3/4
⇒ 2/12 × 1/a = 9/12
⇒ a = <u>9/2</u>
Step-by-step explanation:
1. -9x - 3 - 3 + 2x
-7x - 6
3. 3 - 4x - 7x - 2
-11x - 1
4. 5x - 1 + 3 + 2x
7x + 2
