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3 years ago

Can you please help me?

Mathematics

1 answer:

garri49 [273]3 years ago

4 0

Answer:

6.2

Step-by-step explanation:

$\frac{10.3}{sin(90)} = \frac{x}{sin(37)}$ *Cross multiply*

10.3(sin(37)) = x(sin(90)) *Divide by sin(90) to isolate x*

$x = \frac{10.3(sin(37))}{sin(90)}$ *Solve*

x = 6.19 ≈ 6.2

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6 people equally share bill rs 98.10 how

AnnZ [28]

Answer:

16.35Rs would be paid by everyone.

Step-by-step explanation:

98.10/6

=16.35Rs would be paid by everyone.

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2 years ago

What is the first step in solving: 14 + 2x - 3 = 43?

ch4aika [34]

D. Subtract 14

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3 years ago

In circle C, what is mArc F H?<br><br><br> 31°<br><br> 48°<br><br> 112°<br><br> 121°

faltersainse [42]

Answer:

B. 48

Step-by-step explanation:

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3 years ago

Read 2 more answers

There is a lightning rod on top of a building. From a location 500 feet from the base of the building, the angle of elevation to

Kitty [74]

<h2>Hello!</h2>

The answer is:

The height of the lightning rod is 27.4 feet.

To solve the problem, we need to use the given information about the two points of observation, since both are related (both finish and start at the same horizontal distance) we need to write to equations in order to establish a relationship.

So, writing the equations we have:

We know that the angle of elevation from the base of the buildings is 36°

Also, we know that from the same location, the angle of elevation to the top of the lightning rod is 38°.

Using the information we have:

To the top of the building:

$tan(\alpha )=\frac{DistanceToTheTopOfTheBuilding}{BuildingBase}\\\\tan(36\°)=\frac{DistanceToTheTopOfTheBuilding}{BuildingBase}$

To the top of the lightning rod:

$tan(\alpha )=\frac{DistanceToTheTopOfTheLightningRod}{BuildingBase}\\\\tan(38\°)=\frac{DistanceToTheTopOfTheLightningRod}{BuildingBase}$

Now, isolating we have:

$tan(36\°)=\frac{DistanceToTheTopOfTheBuilding}{BuildingBase}\\\\DistanceToTheTopOfTheBuilding=tan(36\°)*BuildingBase \\\\DistanceToTheTopOfTheBuilding=tan(36\°)*500feet=363.27feet$

Also, we have that:

$tan(38\°)=\frac{DistanceToTheTopOfTheLightningRod}{BuildingBase}\\\\DistanceToTheTopOfTheLightningRod=tan(38\°)*BuildingBase\\\\DistanceToTheTopOfTheLightningRod=tan(38\°)*500feet=390.64feet$

Therefore, if we want to calculate the height of the lightning rod, we need to do the following:

Let "x" the distance to the top of the building and "y" the distance to the top of the lightning rod, so:

$LightningRodHeight=y-x=390.64feet-363.27feet=27.37feet$

Rounding to the nearest foot, we have:

$LightningRodHeight=y-x=390.64feet-363.27feet=27.37feet=27.4feet$

Hence, the answer is:

The height of the lightning rod is 27.4 feet.

Have a nice day!

5 0

3 years ago

It takes Kay 20 minutes to drive to work traveiling 45 mph. Two minutes after she left home this morning, her husband, Dan, star

BARSIC [14]

Answer:

Kay's husband drove at a speed of 50 mph

Step-by-step explanation:

This is a problem of simple motion.

First of all we must calculate how far Kay traveled to her job, and then estimate the speed with which her husband traveled later.

d=vt

v=45 mph

t= 20 minutes/60 min/hour = 0.333 h (to be consistent with the units)

d= 45mph*0.333h= 15 miles

If Kay took 20 minutes to get to work and her husband left home two minutes after her and they both arrived at the same time, it means he took 18 minutes to travel the same distance.

To calculate the speed with which Kate's husband made the tour, we will use the same initial formula and isolate the value of "V"

d=vt; so

v= $\frac{d}{t}$

d= 15 miles

t= 18 minutes/60 min/hour = 0.30 h (to be consistent with the units)

v= $\frac{d}{t}=\frac{15 miles}{0.3 h}=50mph$

Kay's husband drove at a speed of 50 mph

8 0

3 years ago