Well, the first line has a slope of -3, and runs through 0, -1.
a line parallel to that one, will have the same exact slope of -3.
now, we know about this other parallel line that it runs through -3,1, and of course, since is parallel, it has a slope of -3
![\bf \begin{array}{ccccccccc} &&x_1&&y_1\\ &&(~ -3 &,& 1~) \end{array} \\\\\\ % slope = m slope = m\implies -3 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-1=-3[x-(-3)] \\\\\\ y-1=-3(x+3) \implies y-1=-3x-9\implies y=-3x-8](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccccccccc%7D%0A%26%26x_1%26%26y_1%5C%5C%0A%26%26%28~%20-3%20%26%2C%26%201~%29%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0A%25%20slope%20%20%3D%20m%0Aslope%20%3D%20%20m%5Cimplies%20-3%0A%5C%5C%5C%5C%5C%5C%0A%25%20point-slope%20intercept%0A%5Cstackrel%7B%5Ctextit%7Bpoint-slope%20form%7D%7D%7By-%20y_1%3D%20m%28x-%20x_1%29%7D%5Cimplies%20y-1%3D-3%5Bx-%28-3%29%5D%0A%5C%5C%5C%5C%5C%5C%0Ay-1%3D-3%28x%2B3%29%0A%5Cimplies%20%0Ay-1%3D-3x-9%5Cimplies%20y%3D-3x-8)
Answer:
4% used pastels.
Step-by-step explanation:,,
green is the most
5 isnt blue.green,yello or red
The area of the semicircle is A = 1187.9 cm².
<h3>What is the area of a circle?</h3>
The area of a circle with a radius of r is A = πr².
Given that, the diameter of the semicircle is 55 cm.
The radius of the semicircle is,
r = 55/2
The area of a semicircle is given by,
A = (1/2)πr²
Substitute the values,
A = (1/2)π(55/2)²
A = 1187.9
Hence, the area of the semicircle is A = 1187.9 cm².
Learn more about the area of a circle:
brainly.com/question/22964077
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Answer:
90 tickets
Step-by-step explanation:
let the number of tickets be x
and the total amount each has be y
For Jessica
the amount is
y=10x--------1
for Laurie the amount is
Note: she has $360 already
y=360+6x-------2
to find the number of the tickets that will make them have the same amount, let us equate 1 and 2
10x=360+6x
10x-6x=360
4x=360
x=360/4
x=90
Answer:
give me brainliest
Given a line AB with Point C outside it.
Mark point D on the line AB. Join CD
With D as center, and any radius, draw an arc intersecting AB at E, and CD at F.
With C as center, and same radius as before, draw an arc intersecting CD at G.
Open a compass to length EF
Now,with G as center, and compass opened the same radius as before, draw an arc intersecting the previous arc at H.
Draw a line m passing through C and H.
Thus m is the line parallel to AB, and passing through point C
∴m∣∣AB
Step-by-step explanation:
