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3 years ago

PLEASE HELP ME ASAP!!! GIVING BRAINLIESTTO THE QUICKEST ADN RIGHT ANSWER!!!!!!!

Mathematics

2 answers:

tekilochka [14]3 years ago

6 0

Answer:

1/4 times 1/2

Step-by-step explanation:

Zina [86]3 years ago

4 0

Answer:

1/4×1/6

Step-by-step explanation:

All you do is multiply by the reciprocal. (The 6 goes from 6/1 to 1/6 because you flip it around) Also 1/4×1/6= 1/24

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4 3/5 -2 1/3 what is the correct answer?

Dmitrij [34]

You turn 4 and 3/5 into 4 and 9/15 and you turn 2 and 1/3 into 2 and 5/15 and then you subtract to get 2 and 4/15.

3 0

3 years ago

Read 2 more answers

The fish population of Lake Collins is decreasing at a rate of 5% per year. In 2000 there were about

olchik [2.2K]

Answer:

Number of fish in 2006 = 845 fishes (Approx.)

Step-by-step explanation:

Given;

Number of fish in 2000 = 1,150 fishes

Decreasing rate = 5% per year

Find:

Number of fish in 2006

Computation:

Exponential decay function:

F = P[1-r]ⁿ

Number of year = 2006 - 2000

Number of year = 6 year

Number of fish in 2006 = 1,150[1-5%]⁶

Number of fish in 2006 = 1,150[1-0.05]⁶

Number of fish in 2006 = 1,150[0.95]⁶

Number of fish in 2006 = 1,150[0.735]

Number of fish in 2006 = 845.25

Number of fish in 2006 = 845 fishes (Approx.)

4 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs.

Bond [772]

Answer:

it is the reflection in the x-axis

Step-by-step explanation:

3 0

2 years ago

Find the exact value of the trigonometric function given that sinU=-7/25 and cosV=-4/5 (Both U and V are in Quadrant III)

Contact [7]

cosU:-

$\\ \rm\longmapsto \sqrt{1-sin^2U}=\sqrt{1-49/625}=24/25$

As U lies in Q3

cosU=-24/25

sinV

$\\ \rm\longmapsto \sqrt{1-cos^2V}=\sqrt{1-16/25}=3/4$

As V lies in Q3

sinV=-3/5

sin(V-U)=sinVcosU-cosVsinU=(-3/5)(-24/25)-(-4/5)(-7/25)=72/125-28/125=72-28/125=44/125
cos(U-V)=cosUcosV+sinUsinV=(-24/25)(-4/5)+(-7/25)(-3/5)=96/125+21/125=117/125

3 0

2 years ago

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Anettt [7]

Answer:

The total number of U.S. high school students that played on a sports team that year can be estimated to be 7,950,000.

Step-by-step explanation:

From the random sample, we can expect that $\frac{250000}{500000}=\frac{1}{2}$ of all students played on a sports team that year. So in the bigger sample of 15900000 high school students, we can expect $15900000 \cdot \frac{1}{2} = 7950000$ students to have played on a sports team that year.

7 0

3 years ago