52.76= 52+0.7+____ i hate this app a bit

Let X be a binomial random variable with p = 0.7 and n = 10. Calculate the following probabilities from the binomial probability

padilas [110]

Answer:

0.4114

0.0006

0.1091

0.1957

Step-by-step explanation:

Given:

p = 0.7 n = 10

We need to determine the probabilities using table , which contains the CUMULATIVE probabilities P(X $\leq$ x).

a. The probability is given in the row with n = 10 (subsection x = 3) and in the column with p = 0.7 of table:

P(X $\leq$ 3) = 0.4114

b. Complement rule:

P( not A) = 1 - P(A)

Determine the probability given in the row with n = 10 (subsection x = 10) and in the column with p = 0.7 of table:

P(X $\leq$ 10) = 0.9994

Use the complement rule to determine the probability:

P(X > 10) = 1 - P(X $\leq$ 10) = 1 - 0.9994 = 0.0006

c. Determine the probability given in the row with n = 10 (subsection x = 5 and x = 6) and in the column with p = 0.7 of table:

P(X $\leq$ 5) = 0.8042

P(X $\leq$ 6) = 0.9133

The probability at X = 6 is then the difference of the cumulative probabilities:

P(X = 6) = P(X $\leq$ 6) - P(X $\leq$ 5) = 0.9133 — 0.8042 = 0.1091

d. Determine the probability given in the row with n = 10 (subsection x = 5 and x = 11) and in the column with p = 0.7 of table:

P(X $\leq$ 5) = 0.8042

P(X $\leq$ 11) = 0.9999

The probability at 6 $\leq$ X $\leq$ 11 is then the difference between the corresponding cumulative probabilities:

P(6 $\leq$ X $\leq$ 11) = P(X $\leq$ 11) - P(X $\leq$ 5) = 0.9999 — 0.8042 = 0.1957

6 0

3 years ago

Oman said that it is impossible to raise a number to the power of 2 and get a value less than the original number. Do you agree

Eva8 [605]

Oman is wrong, if you raise any decimal number less than one to a power of 2 the number just gets smaller

7 0

3 years ago

Integration by Parts Evaluate e-2x cos(2x) dx.

kifflom [539]

Let

$I = \displaystyle \int e^{-2x} \cos(2x) \, dx[/]texIntegrate by parts:[tex]\displaystyle \int u \, dv = uv - \int v \, du$

with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \cos(2x) \, dx \implies v = \dfrac12 \sin(2x)$

Then

$\displaystyle I = \frac12 e^{-2x} \sin(2x) + \int e^{-2x} \sin(2x) \, dx + C$

Integrate by parts again, this time with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \sin(2x) \, dx \implies v = -\dfrac12 \cos(2x)$

so that

$\displaystyle I = \frac12 e^{-2x} \sin(2x) - \frac12 e^{-2x} \cos(2x) - \int e^{-2x} \cos(2x) \, dx + C\\\\ \implies I = \frac{\sin(2x)-\cos(2x)}{2e^{2x}} - I + C \\\\ \implies 2I = \frac{\sin(2x) - \cos(2x)}{2e^{2x}} + C \\\\ \implies I = \boxed{\frac{\sin(2x) - \cos(2x)}{4e^{2x}} + C}$

6 0

2 years ago

Write and solve an inequality that represents the values of x, in feet.

SVEN [57.7K]

Answer:

x < 16 ft

Step-by-step explanation:

Perimeter = x

If it is less than 16, the equation is:

x < 16

-Chetan K

3 0

3 years ago

Which of the following is true?

Ratling [72]

In this question, we're trying to find the inequality that is true.

To find your answer, we can convert the numbers in the absolute value:

|−5| < 4:

5 < 4 false

|−4| < |−5|:

4 < 5 true

|−5| < |4|

5 < 4 false

|−4| < −5

4 < -5 false

The only true inequality here would be |−4| < |−5|, since it works with the inequality sign.

Answer:

|−4| < |−5|

4 0

3 years ago