Answer: 12 red balls must be added
Step-by-step explanation:
Starting out with 15 balls, 6 red implies 9 blue. If blue remains 9, then we expect red to be 18 for a probability at 2/3. 18-6 = 12
67°C
89°C
Dont quote me on this but I am almost 100 percent sure about it
Correction:
Because F is not present in the statement, instead of working onP(E)P(F) = P(E∩F), I worked on
P(E∩E') = P(E)P(E').
Answer:
The case is not always true.
Step-by-step explanation:
Given that the odds for E equals the odds against E', then it is correct to say that the E and E' do not intersect.
And for any two mutually exclusive events, E and E',
P(E∩E') = 0
Suppose P(E) is not equal to zero, and P(E') is not equal to zero, then
P(E)P(E') cannot be equal to zero.
So
P(E)P(E') ≠ 0
This makes P(E∩E') different from P(E)P(E')
Therefore,
P(E∩E') ≠ P(E)P(E') in this case.
Answer:
10
Step-by-step explanation:
4 * 2.5 = 10
