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2 years ago

10

What is the index?

qrt[5]{7x} " alt=" - 12 \sqrt[5]{7x} " align="absmiddle" class="latex-formula">

2 answers:

Lyrx [107]2 years ago

7 0

12(7x)^1/5

This is simplification into index form, the index itself is the 5th root of 7x if you just wanted to state what it is

klemol [59]2 years ago

6 0

The correct answer is -12×(7x) 1/5 .

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What is the answer to x HURRY PLZ WHO EVER SHOWS WORK WILL GET THE BRAIINLIEST ANSWER AWARD

lakkis [162]

117 divided by g is 19.5

I hope this helps.

8 0

2 years ago

−10 > − 5 or −4 < −20

natima [27]

-10 is less than -5 because negative numbers are farther from 0. Same applies to -4 and -20.

3 0

3 years ago

68.64 divided by 2.4 SHOW WORK PLEASE

34kurt

Answer:28.6

I started by seeing how many 2.4 can go into 68.64. I found that it is pretty easy to find that if you multiply the 2.4 by ten you get 24 so we do that twice and have 48. We then subtract 48 from the 68.64 which leaves us with 20.64. If we multiply 2.4 by 5 we get 12 so once again subtract 12 from that 20.64 and now we are left with 8.64. So now we need to figure out how many more 2.4 are left well it is more than three because three gives us 7.2 so let’s subtract that from it now we are left with 1.44. Now we need to find out what times 2.4 gives us 1.44. Well it would be .6. So now if we add up everything we get the answer of 28.6. Sorry if this very complicated

7 0

3 years ago

Write the slope-intercept form of the equation of the line described.

Ad libitum [116K]

7)

Given the line

$y=-x+2$

We know that the slope-intercept form of the line equation is

$y=mx+b$

here

m is the slope and b is the intercept

Thus, the slope = -1

We know that the parallel lines have the same. Thus, the slope of the parallel line is: -1

Using point-slope of the line equation

$y-y_1=m\left(x-x_1\right)$

substituting the values m = -1 and the point (4, 0)

$y-0 = -1 (x-4)$

Writing in the slope-intercept form

$y = -x+4$

Thus, the slope-intercept form of the equation of the line equation parallel to y=-x+ 2 will be:

$y = -x+4$

8)

<em>Note: </em><em>Your line is a little bit unclear. But, I am assuming the</em>

<em>ine is: </em>y = -x-1

<em />

Given the assumed line

y = -x-1

We know that the slope-intercept form of the line equation is

$y=mx+b$

here

m is the slope and b is the intercept

Thus, the slope = m = -1

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:

slope = m = -1

perpendicular slope = – 1/m = -1/-1 = 1

Using point-slope of the line equation

$y-y_1=m\left(x-x_1\right)$

substituting the values m = 1 and the point (4, 3)

$y - 3 = 1 (x-4)$

Writing in the slope-intercept form

y-3 = x-4

y = x-4+3

y = x - 1

Thus, the slope-intercept form of the equation of the line equation perpendicular to y = -x-1 will be:

y = x - 1

5 0

2 years ago

4 x 234567890123456789

nata0808 [166]

Answer:

Step-by-step explanation:

9.3827156E17 the awnser

4 0

2 years ago

Read 2 more answers