If tan theta is -1, we know immediately that theta is in either Quadrant II or Q IV. We need to focus on Q IV due to the restrictions on theta.
Because tan theta is -1, the ray representing theta makes a 45 degree angle with the horiz axis, and a 45 degree angle with the negative vert. axis. Thus the hypotenuse, by the Pythagorean Theorem, tells us that the hyp is sqrt(2).
Thus, the cosine of theta is adj / hyp, or +1 / sqrt(2), or [sqrt(2)]/2
The secant of theta is the reciprocal of that, and thus is
2 sqrt(2)
---------- * ------------ = sqrt(2) (answer)
sqrt(2) sqrt(2)
Answer:
w^2+
9
+
2
0
Step-by-step explanation:
Answer:
<u>a. 11</u>
<u>b. 9</u>
Step-by-step explanation:
<em>A:</em>
2 x 4 = 8
8 + 3 = 11
<em>B:</em>
-2 x -2 = 4
4 + 5 = 9
Hope this helps! Let me know if it was right!
282
Step-by-step explanation:
C=180-112=68
A=180-68-51=61
sum of exterior angles=112+119+51=282
Answer:
h=128
Step-by-step explanation:
