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3 years ago

What is 5/8 times 4? Then simplify your answer.

Mathematics

2 answers:

Sunny_sXe [5.5K]3 years ago

8 0

5/8 x 4/1 multiply numerators 5 x 4=20 multiply denominators 8 x 1=8 20/8= 5/2 or 2 1/2 hope this helps

scZoUnD [109]3 years ago

4 0

The answer is 2 1/2. Because you need to cross cancel then you take the "freeway", and you get 5/2 and simplified is 2 1/2.And since half equals .5 it would be 2.5 just in case you also needed decimal.

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Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

$\int\limits^5_1 {x/(2+x^{3}) } \, dx$ =f(x)= $x/2+x^{3}$

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)= $[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}$

$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

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2 years ago

Will give brainlisted whoever is correct first. please hurry.

kipiarov [429]

Answer:

32.33 <= m

Step-by-step explanation:

Since we are dealing with below sea level our initial starting point and max level will both be negative values, while our descending rate will also be negative because we are going down. Using the values provided we can create the following inequality...

-400 <= -12m - 12

Now we can solve the inequality to find the max number of minutes that the submarine can descend.

-400 <= -12m - 12 ... add 12 on both sides

-388 <= -12m ... divide both sides by -12

32.33 <= m

3 0

2 years ago