Question

I need help can you explain how to do it​

Answer 1

Answer:

-7.

Step-by-step explanation:

(x²+t²x+t³+8)`=(x²)`+(t²x)`+(t³)`+(8)`=2x*x'+2t*x+t²*x'+3t²;

$x'=\frac{2tx+3t^2}{t^2+2x};$

$x'(-2;-4)=\frac{2*2*4+3*4}{4-8}=-7.$