Answer:
(A) 0.377,
(B) 0.000,
(C) 0.953,
(D) 0.047
Step-by-step explanation:
We assume that having a bone of intention means not liking one's Mother-in-Law
(A) P(all six dislike their Mother-in-Law) = (85%)^6 = (.85)^6 = 0.377
(B) P(none of the six dislike their Mother-in-Law) =
(100% - 85%)^6 =
0.15^6 =
0.000
(C) P(at least 4 dislike their Mother-in-Law) =
P(exactly 4 dislike their Mother-in-Law) + P(exactly 5 dislike their Mother-in-Law) + P(exactly 6 dislike their Mother-in-Law) =
C(6,4) * (.85)^4 * (1-.85)^2 + C(6,5) * (.85)^5 * (.15)^1 + C(6,6) * (.85)^6 = (15) * (.85)^4 * (.15)^2 + (6) * (.85)^5 * .15 + (1) * (.85)^6 =
0.953
(D) P(no more than 3 dislike their Mother-in-Law) =
P(exactly 0 dislikes their Mother-in-Law) + P(exactly 1 dislikes her Mother) + P(exactly 2 dislike their Mother-in-Law) + P(exactly 3 dislike their Mother-in-Law) =
C(6,0) * (.85)^0 * (.15)^6 + C(6,1) * (.85)^1 * (.15)^5 + C(6,2) * (.85)^2 * (.15)^4 + C(6,3) * (.85)^3 * (.15)^3 =
(1)(1)(.15)^6 + (6)(.85)(.15)^5 + (15)(.85)^2 *(.15)^4 + (20)(.85)^3 * (.15)^3 =
0.047
In this problem, we're going to use the 'PEMDAS' method.
First, we're doing the problem in the parenthesis.
44 - 4 = 40
Next in PEMDAS, we need to do the exponent.
6² = 6 x 6 = 36
Then we would do multiplication, but there is nothing to multiply so we move onto division.
40 / 2 = 20
Now we would add, but there is nothing to add so we move onto subtraction.
20 - 36 = -16
Our final answer would be -16.
Hope this helps!~
Tan 18 = opposite side/adjacent side
0.3249 = 4/adjacent side
and adjacent side = 4/0.3249 = 12.31
Now let's apply Pythagoras to find x
4² + 12.31² = x²
16 + 151.55 = x² and x² = 167.55
Then x = √167.55 and x = 12.94 ≈ 13
Answer:
y= 300 - 5/9x
Step-by-step explanation:
0.8y = 240 - 0.5x
divide both sides by 0.8,
y= 300 - 5/9x
-5/9 is your gradient
300 is your y-intercept
Well if she spent 3649 then spend 321 more and more is add so you will add those two then when you get the answer you will add your answer with the money you got on Tuesday and you get your answer.