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andriy [413]
2 years ago
7

The equation of a line is y=6/7 x+7

Mathematics
1 answer:
gogolik [260]2 years ago
7 0

Answer:

Solution given:

y=6/7x+7

Comparing above equation with y=mx+c

we get

m=6/7

a What is the slope of a line parallel to it?

Since for parallel slope are equal ,

slope will be 6/7.

b What is the slope of a line perpendicular to it?

Since for perpendicular line slope is reciprocal to another line but negative so

slope of line is-7/6.

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pentagon [3]
2/8, 2 Over 8 because all your doing is multiplying 1x2 and 4x2
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Find the equation of the line tangent to the graph of f(x)=(lnx)^(4)at x=10
Diano4ka-milaya [45]

Hello,

Step-by-step explanation:

f(x) = ln(x) {}^{4}

(ln(u)') =  \frac{u'}{u}

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4 0
2 years ago
On Monday in Minneapolis, Minnesota, it was 0 °F
klemol [59]

Answer:

-15

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4 0
3 years ago
Read 2 more answers
What are the excluded values of x for <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%2B1%7D%7Bx%5E2-1%7D%20" id="TexFormula1"
NISA [10]
Denominator:

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so excluded values are x =  -1 and x = 1.

Answer D.
8 0
3 years ago
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What is the value of x after these statements if the starting value of x is 3.
kolbaska11 [484]
[A]
3^{2}=9
5^{3}=125
9\neq25

Ignore


[B]
3^{2} = 9
9 \ \textgreater \  3
Yes

3^{3}=27
4( 3^{2})=36&#10;&#10;27 \ \textless \  36
Yes

Therefore
x=3+2=5


[C]
4^{5}=1024&#10;&#10; 5^{4}=625&#10;&#10;1024\ \textless \ 625
No

5^{5}=3125&#10;&#10; 5^{5}=3125&#10;&#10;3125\ \textgreater \ 3125
No

Ignore


[D]
5^{5}=3125&#10;&#10; 2^{5}=32&#10;&#10;3125\ \textgreater \ 32
Yes

5^{2}=25&#10;25\ \textless \ 11
No

Therefore
x=5+8=13


[E]
8\ \textgreater \ 7
Yes

Therefore
x = 13^{2}=169
4 0
3 years ago
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