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3 years ago

Express the height of the tower in terms of trigonometric ratios. A) 35(cos95°) B) 95(tan35°) C) 95(cot35°) D) 95(sin35°)

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

8 0

Answer:

95tan35°

Step-by-step explanation:

Find the diagram attached

Given the following

Adjacent = 95m

Opposite = height of the tower

Angle of elevation = 35degrees

Using SOH CAH TOA

tan theta = opp/adj

Tan 35 = h/95

Cross multiply

95 * tan 35 = h

95tan35 = h

Swap

h = 95tan35

Hence then the height of the tower in terms of trigonometric ratios is 95tan35°

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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What is the distance between the two coordinates points c and b?

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Given the general form of the sinusoidal function, y = AsinB(x - C) + D, match the following items.

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Answer:

$\Delta y = A$ (Amplitude) (Correct answer: 1)

$\omega = B$ (Angular frequency) (Correct answer: 2)

$x_{o} = C$ (Phase shift) (Correct answer: 3)

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Step-by-step explanation:

The general form of a sinusoidal function is represented by the following characteristics:

$y = \Delta y \cdot \sin \omega\cdot (x- x_{o}) + y_{o}$ (1)

Where:

$\Delta y$ - Amplitude.

$\omega$ - Angular frequency.

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$y_{o}$ - Vertical shift.

$x$ - Independent variable.

$y$ - Dependent variable.

In addition, we know that the period associated with the sinusoidal function ( $T$ ) is:

$T = \frac{2\pi}{\omega}$

By direct comparison, we get the following conclusions:

$\Delta y = A$ (Amplitude) (Correct answer: 1)

$\omega = B$ (Angular frequency) (Correct answer: 2)

$x_{o} = C$ (Phase shift) (Correct answer: 3)

$y_{o} = D$ (Vertical shift) (Correct answer: 4)

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3 years ago

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