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krok68 [10]
3 years ago
7

PLZ HELP ASAP WILL MARK BRAINIEST

Mathematics
2 answers:
LekaFEV [45]3 years ago
8 0

Answer:

31) Second number line

32) False

33) x>2

Step-by-step explanation:

31) Since -6<x has only < sign but no = sign, it will be an open dot on top of -6.

Since x≤2 has = sign, it will be a closed dot on top of 2.

So, second number line is the correct option.

32) x < -5 represents all the numbers to the left of -5 on a number line like -6,-7,-8,-9 etc.

Since 4 is on the right side of -5 on the number line, it won't be a solution of the inequality x < -5.

33) x+3 > 5

Subtracting 3 from both the sides of the inequality, we have

x + 3 -3 > 5 - 3

Cancelling out the +3 and -3 from the left side, we have

x > 2

Zolol [24]3 years ago
3 0

1. The 2nd number line represents the inequality.

Explanation:

In words, the inequality reads "negative six is less than x, which is less than or equal to two". On the number line, the open circle at negative six means that -6 is not a solution to the inequality: -6 < x. The point at positive two means that positive two is a solution to the inequality: x ≤ 2. Therefore, all numbers greater than -6 and less than or equal to +2 are solutions to the inequality. This is shown on the second number line.

2. False

Explanation:

In words, the inequality reads "x is less than negative five". This means that all numbers less than -5 are solutions to the inequality. Positive four is not less than negative five, so it is not a solution to the inequality.

3. x > 2

Explanation:

To solve the inequality, we have to move all the terms that do not contain x to one side. This inequality is simple because it only requires one step: subtraction.

Solve for x: x + 3 > 5

1. Subtract 3 from both sides to get x by itself:

x + 3 - 3 > 5 - 3

2. Simplify

x > 2

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A mass weighing 16 pounds stretches a spring (8/3) feet. The mass is initially released from rest from a point 2 feet below the
mezya [45]

Answer with Step-by-step explanation:

Let a mass weighing 16 pounds stretches a spring \frac{8}{3} feet.

Mass=m=\frac{W}{g}

Mass=m=\frac{16}{32}

g=32 ft/s^2

Mass,m=\frac{1}{2} Slug

By hook's law

w=kx

16=\frac{8}{3} k

k=\frac{16\times 3}{8}=6 lb/ft

f(t)=10cos(3t)

A damping force is numerically equal to 1/2 the instantaneous velocity

\beta=\frac{1}{2}

Equation of motion :

m\frac{d^2x}{dt^2}=-kx-\beta \frac{dx}{dt}+f(t)

Using this equation

\frac{1}{2}\frac{d^2x}{dt^2}=-6x-\frac{1}{2}\frac{dx}{dt}+10cos(3t)

\frac{1}{2}\frac{d^2x}{dt^2}+\frac{1}{2}\frac{dx}{dt}+6x=10cos(3t)

\frac{d^2x}{dt^2}+\frac{dx}{dt}+12x=20cos(3t)

Auxillary equation

m^2+m+12=0

m=\frac{-1\pm\sqrt{1-4(1)(12)}}{2}

m=\frac{-1\pmi\sqrt{47}}{2}

m_1=\frac{-1+i\sqrt{47}}{2}

m_2=\frac{-1-i\sqrt{47}}{2}

Complementary function

e^{\frac{-t}{2}}(c_1cos\frac{\sqrt{47}}{2}+c_2sin\frac{\sqrt{47}}{2})

To find the particular solution using undetermined coefficient method

x_p(t)=Acos(3t)+Bsin(3t)

x'_p(t)=-3Asin(3t)+3Bcos(3t)

x''_p(t)=-9Acos(3t)-9sin(3t)

This solution satisfied the equation therefore, substitute the values in the differential equation

-9Acos(3t)-9Bsin(3t)-3Asin(3t)+3Bcos(3t)+12(Acos(3t)+Bsin(3t))=20cos(3t)

(3B+3A)cos(3t)+(3B-3A)sin(3t)=20cso(3t)

Comparing on both sides

3B+3A=20

3B-3A=0

Adding both equation then, we get

6B=20

B=\frac{20}{6}=\frac{10}{3}

Substitute the value of B in any equation

3A+10=20

3A=20-10=10

A=\frac{10}{3}

Particular solution, x_p(t)=\frac{10}{3}cos(3t)+\frac{10}{3}sin(3t)

Now, the general solution

x(t)=e^{-\frac{t}{2}}(c_1cos(\frac{\sqrt{47}t}{2})+c_2sin(\frac{\sqrt{47}t}{2})+\frac{10}{3}cos(3t)+\frac{10}{3}sin(3t)

From initial condition

x(0)=2 ft

x'(0)=0

Substitute the values t=0 and x(0)=2

2=c_1+\frac{10}{3}

2-\frac{10}{3}=c_1

c_1=\frac{-4}{3}

x'(t)=-\frac{1}{2}e^{-\frac{t}{2}}(c_1cos(\frac{\sqrt{47}t}{2})+c_2sin(\frac{\sqrt{47}t}{2})+e^{-\frac{t}{2}}(-c_1\frac{\sqrt{47}}{2}sin(\frac{\sqrt{47}t}{2})+\frac{\sqrt{47}}{2}c_2cos(\frac{\sqrt{47}t}{2})-10sin(3t)+10cos(3t)

Substitute x'(0)=0

0=-\frac{1}{2}\times c_1+10+\frac{\sqrt{47}}{2}c_2

\frac{\sqrt{47}}{2}c_2-\frac{1}{2}\times \frac{-4}{3}+10=0

\frac{\sqrt{47}}{2}c_2=-\frac{2}{3}-10=-\frac{32}{3}

c_2==-\frac{64}{3\sqrt{47}}

Substitute the values then we get

x(t)=e^{-\frac{t}{2}}(-\frac{4}{3}cos(\frac{\sqrt{47}t}{2})-\frac{64}{3\sqrt{47}}sin(\frac{\sqrt{47}t}{2})+\frac{10}{3}cos(3t)+\frac{10}{3}sin(3t)

8 0
3 years ago
What is another way to write the equation 7/8x + 3/4=-6?
kari74 [83]
You can write it as 7/8x = -6 - 3/4 I hope this helps
8 0
3 years ago
Read 2 more answers
If a1 = 8 and an = an-1 + 5 then find the value of a5.
Nimfa-mama [501]

Step-by-step explanation:

A1=8

A2=A1+5 plug 8 into A1 here. After getting the value, put into next equation. And repeat until you get A5

A3=A2+5

A4=A3+5

A5=A4+5

5 0
3 years ago
Plz help.....................
Nata [24]
I'm pretty positive it would be the second one from the top
7 0
3 years ago
Expand the following:<br> a) 3(x + 5)<br> b) 4(x-4)<br> c) 2(5x + 1)<br> d) 7(x-9y)
Tema [17]

Answer:

<h3>a. 3x+15</h3><h3>b. 4x-16</h3><h3>c. 10x+2</h3><h3>D. 7x-63y</h3>

solution,

a. \: 3(x + 5) \\  \:  \:  = 3 \times x + 3  \times 5 \\  \:  \:  = 3x + 15

b. \: 4(x - 4) \\  \:  \:  = 4 \times x - 4 \times 4 \\  \:  \:  = 4x - 16

c. \: 2(5x + 1) \\  \:  = 2 \times 5x + 2 \times 1 \\  \:  \:  = 10x + 2

d . \: 7(x - 9y) \\  \:  = 7 \times x - 7 \times 9y \\  \:  \:  = 7x - 63y

Hope this helps..

Good luck on your assignment..

8 0
3 years ago
Read 2 more answers
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