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krok68 [10]
3 years ago
7

PLZ HELP ASAP WILL MARK BRAINIEST

Mathematics
2 answers:
LekaFEV [45]3 years ago
8 0

Answer:

31) Second number line

32) False

33) x>2

Step-by-step explanation:

31) Since -6<x has only < sign but no = sign, it will be an open dot on top of -6.

Since x≤2 has = sign, it will be a closed dot on top of 2.

So, second number line is the correct option.

32) x < -5 represents all the numbers to the left of -5 on a number line like -6,-7,-8,-9 etc.

Since 4 is on the right side of -5 on the number line, it won't be a solution of the inequality x < -5.

33) x+3 > 5

Subtracting 3 from both the sides of the inequality, we have

x + 3 -3 > 5 - 3

Cancelling out the +3 and -3 from the left side, we have

x > 2

Zolol [24]3 years ago
3 0

1. The 2nd number line represents the inequality.

Explanation:

In words, the inequality reads "negative six is less than x, which is less than or equal to two". On the number line, the open circle at negative six means that -6 is not a solution to the inequality: -6 < x. The point at positive two means that positive two is a solution to the inequality: x ≤ 2. Therefore, all numbers greater than -6 and less than or equal to +2 are solutions to the inequality. This is shown on the second number line.

2. False

Explanation:

In words, the inequality reads "x is less than negative five". This means that all numbers less than -5 are solutions to the inequality. Positive four is not less than negative five, so it is not a solution to the inequality.

3. x > 2

Explanation:

To solve the inequality, we have to move all the terms that do not contain x to one side. This inequality is simple because it only requires one step: subtraction.

Solve for x: x + 3 > 5

1. Subtract 3 from both sides to get x by itself:

x + 3 - 3 > 5 - 3

2. Simplify

x > 2

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Answer:

Option (B). Perimeter of the quadrilateral ABCD= 14.6 units

Step-by-step explanation:

From the figure attached,

Coordinates of the vertices are A(3, 5), B(1, 3), C(3, -1), D(5, 3).

Length of AB = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

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Length of AD = \sqrt{(3-5)^2+(5-3)^2}

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Length of BC = \sqrt{(1-3)^2+(3+1)^2}

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Length of DC = \sqrt{(5-3)^2+(3+1)^2}

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Perimeter of the quadrilateral = AB + AD + DC + BC

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Option (B) is the answer.

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