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AnnZ [28]
3 years ago
12

What is 95.045 greater than less than or equal to 95.545

Mathematics
1 answer:
hoa [83]3 years ago
6 0
95.045 is less than 95.545
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Someone help me with this please
dangina [55]

Answer:

4 number

Step-by-step explanation:

16p+32q=1,280

3 0
3 years ago
Use the graph to find the cost of 6 show tickets
larisa [96]

Answer:

B) 30

Step-by-step explanation:

bottom of graph represents number of tickets, look for 6 then go up till you hit the dot now go to the other side of the graph ( costs) and see which number the line hit which is 30

3 0
3 years ago
Read 2 more answers
The prior probabilities for events A1 and A2 are P(A1) = 0.35 and P(A2) = 0.50. It is also known that P(A1 ∩ A2) = 0. Suppose P(
forsale [732]

Answer:

Step-by-step explanation:

Hello!

Given the probabilities:

P(A₁)= 0.35

P(A₂)= 0.50

P(A₁∩A₂)= 0

P(BIA₁)= 0.20

P(BIA₂)= 0.05

a)

Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)

Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.

b)

Considering that P(BIA)= \frac{P(AnB)}{P(A)} you can clear the intersection from the formula P(AnB)= P(B/A)*P(A) and apply it for the given events:

P(A_1nB)= P(B/A_1) * P(A_1)= 0.20*0.35= 0.07

P(A_2nB)= P(B/A_2)*P(A_2)= 0.05*0.50= 0.025

c)

The probability of "B" is marginal, to calculate it you have to add all intersections where it occurs:

P(B)= (A₁∩B) + P(A₂∩B)=  0.07 + 0.025= 0.095

d)

The Bayes' theorem states that:

P(Ai/B)= \frac{P(B/Ai)*P(A)}{P(B)}

Then:

P(A_1/B)= \frac{P(B/A_1)*P(A_1)}{P(B)}= \frac{0.20*0.35}{0.095}= 0.737 = 0.74

P(A_2/B)= \frac{P(B/A_2)*P(A_2)}{P(B)} = \frac{0.05*0.50}{0.095} = 0.26

I hope it helps!

5 0
3 years ago
If a solution has a ( OH- )= 8.6 × 10-5 what is the pOH
riadik2000 [5.3K]
POH is the -log [ OH- ]. Using this equation, simply find the -log of the OH- concentration to find the pOH:

pOH = - log ( 0.000086 ) = 4.07


6 0
3 years ago
A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life
Tasya [4]

Answer:

(a) <em>H₀</em>: <em>μ</em> ≤ 10. vs. <em>Hₐ</em>: <em>μ</em> > 10.

(b) The test statistic value is 1.86.

(c) The critical value to test the phone manufacturer's claim is 1.301.

(d) The battery life of the new touch screen phone is not more than 10 hours.

Step-by-step explanation:

In this case we need to determine the significance of the claim made by the phone manufacturer, that the battery life of the new touch screen phone is more than twice as long as that of the leading product.

The information provided is:

\bar x=10.5\\s=1.8\\n=45

(a)

The hypothesis can be defined as follows:

<em>H₀</em>: The battery life of the new touch screen phone is not more than 10 hours, i.e. <em>μ</em> ≤ 10.

<em>Hₐ</em>: The battery life of the new touch screen phone is more than 10 hours, i.e. <em>μ</em> > 10.

(b)

As the population standard deviation is not provided, we will use a <em>t</em>-test for single mean.

Compute the test statistic value as follows:

 t=\frac{\bar x-\mu}{s/\sqrt{n}}=\frac{10.5-10}{1.8/\sqrt{45}}=1.86

The test statistic value is 1.86.

(c)

The significance level of the test is, <em>α</em> = 0.10.

The degrees of freedom will be:

df=n-1=45-1=44

Compute the critical value as follows:

t_{0.10, 44}=1.301

*Use a <em>t</em>-table for the value.

Thus, the critical value to test the phone manufacturer's claim is 1.301.

(d)

Decision rule:

If the test statistic value is less than the critical value then the null hypothesis will be rejected and vice-versa.

 t = 1.86 > t₀.₁₀, ₄₄ = 1.30

The calculated <em>t</em>-value of the test is more than the critical value.

The null hypothesis will not be rejected.

Thus, it can be concluded that the battery life of the new touch screen phone is not more than 10 hours.

6 0
3 years ago
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