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Ivahew [28]
3 years ago
7

Find the measure of mLIK

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
5 0

big titty bonkers from men of all ages and cows

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-
ollegr [7]

Answer:

x = 2

y = -3

z = 4

( 2 , -3, 4 )

Step-by-step explanation:

x + y + z = 3 ---- i

x – y =5 ---- ii

y - z = -7 ---- iii

ii + iii

x - z = -2 ---- iv

i + ii

2x + z = 8 --- v

iv + v

3x = 6

x = 2

x=2 substitute for v

z = 4

x =2 substitute for ii

y = -3

5 0
3 years ago
A ball is thrown in the air from a height of 3 m with an initial velocity of 12 m/s. To the nearest tenth of a second, how long
wel

Answer: 0.3m/s

Step-by-step explanation:

Height/ velocity

3m/12m per sec

Time= 0.25metres per seconds

To the nearest tenth, 0.3m per seconds

5 0
3 years ago
Y = -8x2 + 665x – 5754
Burka [1]

Answer:

Is the -8x2 a -8x squared? Because the answer of this problem can be different.

Step-by-step explanation:

3 0
3 years ago
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
Janine made a cylindrical vase in which the sum of the lateral area and area of one base
Vinil7 [7]
Is this multiple choice

5 0
3 years ago
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